Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
Hey, don’t call for that link thing. It’s fake. Here’s how I solved this: x = [35(80%) + 70(25%)]/(35 + 70) = 43.3%
The answer is 43.3%
Answer: 45
Step-by-step explanation:
2,000
10,000 divided by 5 = 2,000
Answer:
Heyyyy!!
The answer is 66.9
please read the explanation... it will help... I promise
Step-by-step explanation:
Okay... Here we go...
The context mentions that the two quadrilaterals are similar... meaning their sides are proportional...
So... you basically have to find the scale factor...
(the math itself is easier than the explanation...
51/16 = 3.1875 (that is the number we multiplied the sides of quadrilateral FGHI to get quadrilateral JKLM...
so to get side JK all you have to do is multiply that scale factor by side FG... which after the use of a calculator results in 66.9 (i rounded, and used a calculator... lol)
but yeah... i hope this helps...
