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2 years ago

Please help me solve this!!! V=1/3bh

Mathematics

2 answers:

Talja [164]2 years ago

7 0

Answer:

the answer is v=bh/3

Step-by-step explanation:

I solve for V since you didn't put what letter you wanted the question to be solved for.

hope this helps.

Kobotan [32]2 years ago

3 0

Answer:

What?

Step-by-step explanation:

Okay, the formula, then what?

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Pls answer the question important

Sladkaya [172]

Step-by-step explanation:

no they are not parallel

4 0

3 years ago

Read 2 more answers

Write 5(6x+4)-2(5x-2) in the form a(bx+c) where a,b and c integers and a>1

Tamiku [17]

Answer:

Step-by-step explanation:

$5(6x+4)-2(5x-2)\qquad\text{use distributive property}\ a(b+c)=ab+ac\\\\=(5)(6x)+(5)(4)+(-2)(5x)+(-2)(-2)\\\\=30x+20-10x+4\qquad\text{combine like terms}\\\\=(30x-10x)+(20+4)\\\\=20x+24$

$20x=4\cdot5x\\\\24=4\cdot6\\\\20x+24=4(5x+6)$

6 0

2 years ago

Solve for x.........

Ket [755]

Answer:

x = 12

Step-by-step explanation:

Angle QPR + Angle PQR = Angle HRQ

$30 + 4x + 2 = 8 + 6x \\ (6 - 4)x = 30 + 2 - 8 \\ 2x = 24 \\ x = 12$

8 0

2 years ago

Read 2 more answers

Which of the following is an arithmetic sequence?

Travka [436]

Step-by-step explanation:

C. n 1 2 3 4

an 3 6 9 15

hope this helps you

have a great day : )

5 0

2 years ago

Write an equation of the circle with center (3,-2) and radius 6

Lubov Fominskaja [6]

Answer:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

Step-by-step explanation:

We want to write the equation of a circle with a center at (3, -2) and a radius of 6 units.

Recall that the equation of a circle is given by:

$\displaystyle (x-h)^2 + (y-k)^2 = r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (3, -2), h = 3 and k = -2. r = 6. Substitute:

$\displaystyle (x-(3))^2 +(y-(-2))^2 = (6)^2$

Simplify:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

In conclusion, the equation of the circle will be:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

8 0

2 years ago