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Mashutka [201]
3 years ago
15

Name the tools in plant propagation.Q18.16.17.19.20.please po asap​

Computers and Technology
1 answer:
Agata [3.3K]3 years ago
6 0
16. Branch or tree cutter
17.paint tape
18. Knife
19. Pots
20. Waterer
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Write a WHILE loop that lets the user enter a number.
balandron [24]

Answer:

while True:

   number = int(input("Enter a number: "))

   product = number * 10

   if product > 100:

       break

print(str(product))

Explanation:

Create a while loop that iterates until a specific condition is created inside

Ask the user for the input

Multiply the input and put the result in product

Check if the product is greater than 100. If it is, stop the loop using break keyword

When the loop is done, print the product

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4 years ago
__________ locks can be changed after they are put in service, allowing for combination or key changes without a locksmith and e
Vladimir79 [104]

Answer:

Programmable.

Explanation:

Programmable locks can be changed after they are put in service, allowing for combination or key changes without a locksmith and even allowing the owner to change to another access method (key or combination) to upgrade security. This type of lock are operated using a programmable plastic card and are typically smart.

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Which can be used to code a simple web page? CSS JavaScript Text editor Web browser
melisa1 [442]

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On what basis can you categorize the generations of computers
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what the answer to this question....


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You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
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Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

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}

else

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