Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
I believe there is only one outlier (shown in this picture) mostly because it is the farthest from this dotted mess
Answer:
7
Step-by-step explanation:
7^-1/7^-2=7
Your answer is: 8x^4 y^5/7.
Answer:
A
Step-by-step explanation:
(f + g)(x) = f(x) + g(x) , thus
f(x) + g(x)
= 4x + 1 + x² - 5 ← collect like terms
= x² + 4x - 4 → A
