Kim can paint 4 walls in 5 hours. How long will it take to paint 7 walls?

What is the following product

frosja888 [35]

I would pick C sorry if it’s wrong

3 0

3 years ago

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The area of the entire figure below is 1 square unit.<br> What is the area of the striped rectangle?

Illusion [34]

Answer:

3/4 * 2/5

Step-by-step explanation:

Areas is L * W

(1/5 + 1/5) * (1/4 + 1/4 + 1/4) = 2/5 * 3/4

5 0

2 years ago

Read 2 more answers

Hello please help with my question, I will give brainlyest!

lilavasa [31]

No, John is incorrect.

<h3>Correct work shown:</h3>

$\sf x^2 - 6x - 7 = 0$

$\sf x^2 - 6x = 7$

$\sf x^2 - 6x + 9= 7 + 9$

$\sf (x-3)^2= 16$

$\sf x-3=\pm \sqrt{16}$

$\sf x-3= \pm 4$

$\sf x= + 4 + 3 \quad or \quad x = -4 + 3$

$\sf x= 7 \quad or \quad x = -1$

The correct answer should be x = 7 or x = -1

3 0

2 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em> $f$ <em> is a continuous function on </em> $[a,b]$ <em>, then</em>

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

The students at Norton School were asked to name their favorite type of pet. Of the 430ilar results, about students surveyed, 25

elena-s [515]

Answer: 60

Step-by-step explanation:

From the question, we are informed that 430 students were surveyed and 258 said that their favorite type of pet was a dog. The fraction/decimal of those that chose dog as their favorite pet will be:

= 258/430

= 3/5

= 0.6

Suppose that only 100 students were surveyed, the number of students that would say that a dog is their favorite types of pet will be:

= 0.6 × 100

= 60

5 0

3 years ago