Math Problem! please help!

Please help me with the domain and range this is Algebra 2

adelina 88 [10]

Domain: The set of all real numbers
We can plug in any x value we want and there aren't any restrictions. There aren't any holes, jumps, gaps, or asymptotes

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Range: Only one value is in the range and it is the value 2. We can write this as {2}. The curly brackets indicate "set". It is possible to have a set of only 1 item inside.

The range is the set of y value outputs. In this case, the output is 2 because we have a horizontal line. No matter what the x input is, the output is always 2. This is known as a constant function. The output is constantly the same.

3 0

3 years ago

Which value in this data set is an outlier? 4, 5, 1, 7, 4, 5, 8, 9, 6, 5, 4, 9, 7 A. 1 B. 2 C. 3 D. 9

boyakko [2]

tha answer is b, 1111111111111111111

5 0

3 years ago

Plz help ill give you brainlist

tamaranim1 [39]

Hey there!

To find the markup percentage, you must use your formula for percent markup:
profit/cost*100

Because your profit is found by subtracting 13-10, 3, your profit would be 3. You also know that your cost is 10.

Now, plug in your values:
3/10*100

And simplify:
3/10*100
0.3*100
=30

Therefore, your percent markup would be about 30%.

Hope this helps and have a nice day!

5 0

4 years ago

In a random sample of 25 people, the mean commute time to work was 33.9 minutes and the standard deviation was 7.2 minutes. Ass

Phoenix [80]

Answer:

$33.9-1.32\frac{7.2}{\sqrt{25}}=31.999$

$33.9+1.32\frac{7.2}{\sqrt{25}}=35.801$

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}}$

And replacing we got:

$ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=33.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=7.2 represent the sample standard deviation

n=25 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,24)".And we see that $t_{\alpha/2}=1.32$