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egoroff_w [7]
3 years ago
5

-6c + 7 = -31 What does C equal???

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0

Answer:

c=19/3

Step-by-step explanation:

Gennadij [26K]3 years ago
4 0
Answer: 19/3

Explanation: The first thing I do is subtract 7 from both sides;
-6c=-38;
then, divide -6 from both sides
c=38/6 then simplify the fraction 19/3
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Answer:

Length x Width x Height

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On the number line about RT = 1/6. Point s ( not shown) is located between point r and point t. Which value is below is a possib
mojhsa [17]

Answer: you do the one

Step-by-step explanation:

Yeah

7 0
3 years ago
Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths
kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment


Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

3 0
2 years ago
Consider the following quadratic equation x^2 =4x -5. How many solutions does it have?
aleksandrvk [35]
The answer for your question is C.
5 0
3 years ago
Read 2 more answers
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
4 years ago
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