Answer:
Option D
Step-by-step explanation:
A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.
Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval?
We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.
Answer:
875cm^2
Step-by-step explanation:
since opposite sides are equal
3x-y=2x+y
x=2y
y=x/2 ....(i)
thus new length=2x+y
=2x+(x/2) [using (i)]
=(4x+x)/2
l=5x/2 .....(ii)
now,
perimeter=2(l+b)=120cm
l+b=60cm
from figure and using (ii)
[5x/2]+2x-3=60
[5x+4x-6]/2=60
9x-6=120
9x=126
x=126/9
x=14 ..........(iii)
substitute (iii) in (i)
y=14/2
y=7 ...........(iv)
From figure,
length=2x+y [using (iii) and (iv)]
=2x14+7
length=35cm
breadth=2x-3
=2x14-3 ....[using(iii)]
=28-3
breadth=25cm
now,
Area=lxb
=35x25
=875cm^2
Assuming that <span>4^2-6(2^x)-16=0 is correct, we can rearrange it as:
</span><span>-6(2^x) + 4^2 - 16=0
Are you sure it's not </span>6(2^x) + 4^2 - 16=0 ?
If 6(2^x) + 4^2 - 16=0 is correct, then
6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)
Answer:
Three times
Step-by-step explanation:
Given
Figures: Rectangular Prism and Rectangular Pyramid
Let the dimension of the prism be:
Amount of sand used is the volume (V1) and it is calculated using;
Since the pyramid has the same base area and height as the prism, the its dimension would be:
Amount of sand used is the volume (V2) and it is calculated using;
So, we have:
Substitute lwh for V1 in the second equation
Multiply both sides by 3
Reorder
<em>Hence, the amount of sand used in building the prism is three times the amount of sand used in building the pyramid</em>
Answer:
Perimeter = 16 units
Area = 15 squared units
Step-by-step explanation:
ABCD is a rectangle.
It's length l = 5 units
and width w = 3 units
Perimeter of ABCD = 2(l + w) = 2(5 + 3) = 2*8 = 16 units
Area of ABCD = 5*3 = 15 squared units.
