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pshichka [43]
2 years ago
10

A jacket is marked down 55% off the original price. If the original price was $160.00, what is the sale price of the jacket befo

re sales tax?
Mathematics
1 answer:
Naya [18.7K]2 years ago
3 0

Answer:

72

Step-by-step explanation:

because when you do 55% out of 160 it will give you 88 which you subtract from 160 and then you will end up with 72

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Solve the system <br> 5x+3y=-9 &amp;- 2x+y=8
lianna [129]
5x+3y=-9
-2x+y=8

The first step is the trickery (and quite frankly, hardest to explain) part. You need to multiply one equation by a number that will create one variable to be the negative version of the other...(Confusing, right? Don't worry, I'll show you)

We are going to solve for X first.

We will multiply the second equation by -3
5x+3y=-9
-3(-2x+y)=(-3)8

Now simplify:
5x+3y= -9
6x-3y= -24

Now combine the two equations (add them together)
11x= -33
Divide by 11
X=-3

Now plug X in to one of the first equations:
5(-3)+3y= -9
-15+3y =-9
3Y= 6
Y= 2


So your final answer is:
x= -3
Y= 2

Hope this helps!
3 0
3 years ago
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A bus picks up passengers at a bus stop every 12 minutes in the morning. Suppose Adrian arrives at the bus stop at a random time
allsm [11]
I’m not too sure but i thinks it’s B
5 0
3 years ago
Let u,v,wu,v,w be three linearly independent vectors in R7R7. Determine a value of kk, k=k= , so that the set S={u−3v,v−2w,w−ku}
11Alexandr11 [23.1K]

Answer:

1/6

Step-by-step explanation:

For a set of vectors a, b and c to be linearly dependent, the linear combination of the set of vectors must be zero.

C1a + C2b + C3c = 0

From the question, we are given the set S={u−3v,v−2w,w−ku}, the corresponding vectors are a(0, -3, 1), b(-2,1,0) and c(1,0,-k)

The values in parenthesis are the ccoefficients of w, v and u respectively.

On writing this vector as a linear combination, we will have;

C1(0, -3, 1) + C2(-2,1,0) + C3(1,0,-k) = (0,0,0)

0-2C2+C3 = 0........ 1

-3C1+C2 = 0 ........... 2

C1-kC3 = 0 ….......... 3

From equation 2, 3C1 = C2

Substituting into 1, -2(3C1)+C3 = 0

-6C1+C3 = 0

-6C1 = -C3

6C1 = C3.…..4

Substitute 4 into 3 to have

C1-k(6C1) = 0

C1 = k6C1

6k = 1

k = 1/6

Hence the value of k for the set of vectors to be linearly dependent is 1/6

6 0
2 years ago
3 lb 5 oz X 6 = __lb __ oz
hoa [83]
19lbs 14 ounces because 16 oz= 1lb
6 0
3 years ago
What is the slope of y = 4 - 2x
NISA [10]

compare with y=mx+c

then

y=4-2x

y=-2x+4

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2 years ago
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