Answer:
- resistance: (2r +5)
- current: (3i +4)
Step-by-step explanation:
The factors of the given expression are ...
6ir +15i +8r +20 = (3i +4)(2r +5)
Which factor is current and which is resistance is not clear. Usually, resistance is referred to using the variable r, so we suppose the expressions are supposed to be ...
resistance: (2r +5)
current: (3i +4)
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
__
You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
__
Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Is there a graph or chart? Or a word problem that tells us some information
Answer: The number in the tenth's place is <u>5</u>
Step-by-step explanation:
There is no ones place in decimals
41.<u>5</u>3
the tenth's place come first then the hundredth's and so on.
