As shown in the figures given :
For Figure 1 : perimeter = 8 units [As can be seen in the figure]
For figure 2(with 2 octagons) : perimeter = 8 × 2 - 1 = 15 units [since 1 side is common ]
For figure 2(with 3 octagons) : perimeter = 8 × 3 - 2 = 22 units [since 2 sides is common ]
If one more octagon is added
then perimeter = 8 × 4 - 3 = 29 units [since 3 sides will be common ]
Answer:
I thought is should only take pic of 1 question
Step-by-step explanation:
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Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
∠B + ∠B` = 180°
The Sine Law:
10 / sin B` = 9.2 / sin 60°
10 / sin B` = 9.2 / √3/2
sin B` = 0.94133
B` = sin^(-1) 0.94133
Answer:
C ) ∠B` = 109.73°, ∠B = 70.27°
Answer:
Jacey has 48 rocks. Carter has 6 rocks.
If Carter and Jacey are the only factor owners of 54 rocks
We divide 48 by 8 = 6 rocks: 42 difference;
Which is also 54 as 6 + 48 = 54
They now have 48 difference
6,6, 6,6, 6,6, 6,6 = 48
We see 48 - 6 = 42.
We also see 48 + 6 = 54
54=6 = 48
48 difference is the denominating divider; meaning 48/8 = 6 is how we first find the answer before adding on the 6 to show the difference of 8 equal shares.
