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9966 [12]
3 years ago
7

Sam’s fish tank has a base area of 187 in2 and a height of 16

Mathematics
1 answer:
inessss [21]3 years ago
7 0

997 1/3 in 3

hope it helps

fhcdfyxvbonmjcf

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The physics department of a college has 8 male professors, 11 female professors, 16 male teaching assistants, and 6 female teach
Lera25 [3.4K]
To determine the probability that one or the other circumstances will occur, you will count the number of possible outcomes and divide it by all the possible outcomes.

#of female teaching assistants + # of male teaching assistants + # of female professors

6 + 16 + 11 = 33

Total = 41

33/41 = 80

There is a approximate 80% probability that one or the other will occur.
6 0
3 years ago
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Bluepoint's current population is 7,353 residents, which is 14% smaller than at the time of its founding. What was the populatio
valina [46]

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8,382.42

Step-by-step explanation:

4 0
3 years ago
If a 2-kg block compresses a spring 800mm from its relaxed state, how much potential energy does the block have due to the sprin
Tju [1.3M]

Answer:

8 Joule

Step-by-step explanation:

Mass of block = 2 kg

Displacement = x = 800 mm = 0.8 m

Spring constant = k = 25 N/m

Potential Energy of a spring

Work done = Difference in Potential Energy

Work Done = Δ P.E.

\Rightarrow \Delta\ P.E.=\frac{1}{2}kx^2

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⇒P.E. = 8 Nm = 8 Joule

Here already the spring constant and displacement is given so the mass will not be used while calculating the potential energy.

5 0
3 years ago
5-2 ????=7-5 ???? which value of x is the solution to the above equation?
saw5 [17]
5-2x=7-5x
-2x+5x=7-5
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8 0
4 years ago
Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form? 5x + 3y = 18 5x – 3y = 30
ddd [48]
\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad 
D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0})
\\\\\\
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}(x-3)

\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3)
\\\\\\
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bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.
6 0
3 years ago
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