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3 years ago

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What's the standard for me

1 answer:

Alexeev081 [22]3 years ago

4 0

CCSS5 IDK OK IM GUESSING IDK U

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Write in simplest form. <br> n+1/7=2/3

ziro4ka [17]

I hope this helps you

n=2/3-1/7

n=2.7/3.7-1.3/7.3

n=14/21-3/21

n=11/21

7 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

2 years ago

Wha'z y'all favo songg

Vesnalui [34]

I don’t listen to song. It’s HARAM. I’m Muslim. :))

3 0

2 years ago

Read 2 more answers

Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0

artcher [175]

Answer:

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

$f(x,y) = f(0,0) + \frac{df(0,0)}{dx} x + \frac{df(0,0)}{dy} y + \frac{1}{2} \frac{d^2f(0,0)}{dx^2} x^2 +\frac{1}{2} \frac{d^2f(0,0)}{dy^2}y^2 + \frac{d^2f(0,0)}{dydx} x*y$

So let's find all the terms:

Remember that:

$\frac{dsin(ax)}{dx} = a*cos(ax)$

$\frac{dcos(ax)}{dx} = -a*cos(ax)$

f(0,0) = sin(0*0) = 1.

$\frac{df(0,0)}{dx}*x = y*cos(0*0)*x = x*y$

$\frac{df(0,0)}{dy} *y = x*cos(00)*y = x*y$

$\frac{1}{2} \frac{d^2f(0,0)}{dx^2}*x^2 = -\frac{1}{2} *y^2*sin(0*0)*x^2 = 0$

$\frac{1}{2} \frac{d^2f(0,0)}{dy^2}*y^2 = -\frac{1}{2} *x^2*sin(0*0)*y^2 = 0$

$\frac{d^2f(0,0)}{dxdy} x*y = (cos(0*0) -x*y*sin(0*0))*x*y = x*y$

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

6 0

2 years ago

7 million x 12millon =<br><br> WILL MAKE BRAINLIEST

astra-53 [7]

Answer:

84000000000000

Step-by-step explanation:

7000000 times 12000000

84000000000000

7 0

2 years ago

Read 2 more answers