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Anestetic [448]
3 years ago
5

Describe two ways to check whether algebraic expressions are equivalent.​

Mathematics
1 answer:
Ghella [55]3 years ago
7 0
Left side right side check! that’s only one i know sorryyyy
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(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)
Elena L [17]

Answer:

\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

Step-by-step explanation:

\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1}  }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}

= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3}  - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a)} {2a+1}

= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

6 0
4 years ago
What is the slope? <br><br> A. 0<br> B. Undefined<br><br> Please help!
IrinaVladis [17]
A.0 is the slope according to the picture .
7 0
3 years ago
Read 2 more answers
Leonard purchases a model boat kit for $67.53. He uses a coupon for $25 off a purchase of $50 or more. What is the discounted pr
DerKrebs [107]
Given that the original price of the model boat kit is $67.53 and he has a coupon of $25 off if a purchase is $50 or more. Since the purchase is more than $50, we will deduct 25 from 67.53 so the discounted price of the model boat kit would be $42.53. Hope this answers your question.
8 0
4 years ago
Solve (5y+2)(y+2)=3(5y+2)
DiKsa [7]

Answer:

y=1, y=-2/5

Step-by-step explanation:

7 0
3 years ago
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The swimming pool at Spring Valley High School is a rectangle with a width of 70 meters and a length of 30 meters. Around the pe
kotykmax [81]

The expression that can be used to find the area of the tiled floor is 4w² + 200w

<h3>Area of rectangle</h3>

  • Original rectangle:

Length = 70 Meters

Width = 30 meters

Area = length × width

= 70 × 30

= 2100

  • New rectangle(including tiled floor):

Length = 70 + 2w meters

Width = 30 + 2w meters

Area = length × width

= (70+2w) (30+2w)

= 2100 + 140w + 60w + 4w²

= 4w² + 200w + 2100

Area of the tiled floor = Area of new rectangle - area of old rectangle

= (4w² + 200w + 2100) - 2100

= 4w² + 200w + 2100 - 2100

= 4w² + 200w

Learn more about area of rectangle:

brainly.com/question/13048427

#SPJ1

6 0
2 years ago
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