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Alex
3 years ago
6

Please a need the answers an the solution please help with the correct answers

Mathematics
1 answer:
marshall27 [118]3 years ago
7 0
Starting at the top left table and then to the one below it
1. -6 -2 2 6 10
2. -17 -11 -5 1 7
3. -42 -26 -10 6 22
4. -5 -2 1 4 7
5. -3 1 5 11 15
6. -4 -2 0 -2 -4

All right, and for the graph, it’s fairly simple. Using table 1, you would use your x and y values and put them in parentheses like so: (x , y) for example, using the two given values, you would have (-2 , -6) this would be your first point. After marking all the points, connect them to have your line
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The question is in the picture​
otez555 [7]

Answer:

x=27.8

Step-by-step explanation:

first, you need to find y. 2y-5=65. 65+5 is 60 and you are left with 2y=70. to get the 2 off of the y you divide everything by 2. 70/2 is 35 therefor y=35. Now you plug that into the other equation (2x+y) and get 2x+35 which is equal to segment 90.6 so 2x+35=90.6. subtract 35 on both sides and you have 2x=55.6. To get the 2 off the x, we divide everything by 2. all of that divided by 2 is x=27.8

5 0
3 years ago
Please someone help!!!
agasfer [191]

Answer:

Step-by-step explanation:

A, B and C must be real numbers, and A and B are not both zero (which would cause division by zero in the calculation of the slope).

3 0
4 years ago
Geometry proofs. Prove Angle B = Angle C
koban [17]

Answer: It is vertical

Step-by-step explanation:

8 0
3 years ago
Car A has an initial value of 30,000 and depreciates at a rate of 20% per year. Car B has an initial value of 20,000 and depreci
Doss [256]

Answer:

The value of Car B will become greater than the value of car A during the fifth year.

Step-by-step explanation:

Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.

In the attached excel file, the following are used:

Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000

Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000

Annual Depreciation expense of Car B in Year 7 =  Beginning value of Car B in Year 7 = 2,000

Conclusion

Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.

Download xlsx
4 0
3 years ago
Read 2 more answers
What is the value of the expression below when y=7?<br><br><br> y2+5y+6
Daniel [21]

Answer:

90

Step-by-step explanation:

y^2 + 5y + 6 =

(7)^2 + 5(7) + 6 =

49 + 35 + 6 =

84 + 6 =

90

5 0
3 years ago
Read 2 more answers
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