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Alecsey [184]
3 years ago
6

I NEED HELP WITH THIS I DONT UNDERSTAND IT

Mathematics
1 answer:
nadezda [96]3 years ago
8 0
16.935 I got a question on a test hope this helps):
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Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

5 0
3 years ago
Simplify the expression 5r + 8r​
S_A_V [24]

Answer:

13r

Step-by-step explanation:

7 0
3 years ago
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Slove the equation<br> 6x+4/5=8
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6x+4/5=8 subtract 6x from both sides 4/5=8-6x multiply both sides by 5 to get rid of the fraction 4=40-30x divide both sides by 2 2=20-15x add 15x to both sides 15x+2=20 subtract 2 from both sides 15x=18 divide both sides by 15 x=1.2
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3 years ago
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What will the y-coordinate/value be for A' (A
Nataliya [291]

what are the coordinates if you tell me that I can help you

3 0
2 years ago
In an all boys school, the heights of the student body are normally distributed with a mean of 71 inches and a standard deviatio
Vika [28.1K]

Answer: the interval of heights that represents the middle 95% of male heights from this school is between 66 inches and 76 inches.

Step-by-step explanation:

Let x be a random variable representing the heights of males from this school. With the mean and standard deviation given, then the Empirical Rule says the that

1) About 68% of the x values lie between 1 standard deviation below and above the mean.

2) About 95% of the x values lie between 2 standard deviations below and above the mean.

3) About 99.7% of the x values lie between 3 standard deviations below and above the mean.

From the information given,

mean = 71 inches

Standard deviation = 2.5 inches

We want to determine where 95% of x values lies. This is 2 standard deviations from the mean Therefore,

2 standard deviations = 2 × 2.5 = 5 inches

The heights are

71 - 5 = 66 inches and

71 + 5 = 76 inches

7 0
3 years ago
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