Answer:
The slope of segment EF is the same as the slope of segment E prime H prime.
Step-by-step explanation:
The center of dilation is located at (0,1) and E is located at (0,5), then, x-coordinate of E' is 0.
The distance between E and the center of dilation is 5-1 = 4
The distance between E' and the center of dilation has to be 3*4 = 12
Therefore, E' is located at (0,13)
The center of dilation is located at (0,1) and H is located at (1,1), then, y-coordinate of H' is 1.
The distance between H and the center of dilation is 1-0 = 1
The distance between H' and the center of dilation has to be 3*1 = 3
Therefore, H' is located at (3,1)
slope of segment EF = (1 - 5)/(1 - 0) = -4
slope of segment E'H' = (1 - 13)/(3 - 0) = -4