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3 years ago

In a quiz just some middle school work anyone who can help me plsss

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

わからない、ごめんなさい。ポイントが欲しかったです笑

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago

Y’all I need help, MATH, please correct answer and how you did it:)

Y_Kistochka [10]

21 I think I'm not sure tho

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3 years ago

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Have I worked out the following right:

Studentka2010 [4]

Answer: I think the answer is 173.25

Step-by-step explanation:

To find that you have to times them.

15.0*11.55 = 173.25

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3 years ago

Which of the following equations describes the line shown below? (1, 10) (-3, 2)

Greeley [361]

(1,10)(-3,2)
slope = (2-10) / (-3-1) = -8/-4 = 2

y = mx + b
slope(m) = 2
(1,10)...x = 1 and y = 10
now we sub and solve for b, the y int
10 = 2(1) + b
10 = 2 + b
10 - 2 = b
8 = b

equation is : y = 2x + 8.....or 2x - y = -8

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3 years ago

I NEED HELP LIKE REALLY REALLY FAST

damaskus [11]

Answer:

56 inches I believe.

I'm not 100% sure.

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3 years ago

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