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3 years ago

The value of a new $5400 sailboat decreases 10% per year. Find its value after 5 years. Round to the nearest penny.

Mathematics

1 answer:

Furkat [3]3 years ago

5 0

Answer:

FV= $3,352.98

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $5,400

Number of periods (n)= 5 years

Interest rate (i)= 10%

To calculate the future value (FV), we need to use the following formula:

FV= PV / (1 + i)^n

FV= 5,400 / (1.1^5)

FV= $3,352.98

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Don't answer if you don't know

SIZIF [17.4K]

0.10d + 0.25q = 3.55
q = d + 3

0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes

q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters

3 0

3 years ago

How do you solve this don’t mind the (f) that’s just the problem number

zavuch27 [327]

Hello,
You need to evaluate the equation, so:
3xˆ2+14x+8 --> 17xˆ2+8. Hop this helps!

~Brainliest

3 0

2 years ago

Evaluate the expression if a=2,b=-3,C=-1, and D=4 -2(b^2-5c)

Alenkasestr [34]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

Equivalent value = -28

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \: - 2( {b}^{2} - 5c)$

( put the values )

$\qquad❖ \: \sf \: - 2 \{( - 3) {}^{2} - 5( - 1) \}$

$\qquad❖ \: \sf \: - 2(9 - (- 5))$

$\qquad❖ \: \sf \: - 2(9 + 5)$

$\qquad❖ \: \sf \: - 2 \times 14$

$\qquad❖ \: \sf \: - 28$

$\qquad \large \sf {Conclusion} :$

-2(b² - 5c) = -28

7 0

1 year ago

Find the value of w A. 141 B. 110 C. 80 D. 100

saw5 [17]

Answer:

141

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

We know z+70 = 180 since they form a straight line

z = 110

z = 1/2 ( 79+w)

110 = 1/2 ( 79+w)

220 = 79+w

220-79 = w

141 =w

5 0

2 years ago

What is x? I will give brainliest if you explain your answer.

horsena [70]

Answer:

x = {0, π/2, 3π/2, 2π}

Step-by-step explanation:

cotx cos x - cot x = 0
cotx( cosx - 1) = 0

1. cotx = 0

x = π/2 + πn
In the interval [0, 2π] we have π/2 and 3π/2

2. cosx = 1

x = 0 + 2πn
In the given interval we have 0 and 2π

So the solution set is:

x = {0, π/2, 3π/2, 2π}

3 0

2 years ago