All categories

3 years ago

Omg lol hey nice weather

Mathematics

1 answer:

Simora [160]3 years ago

7 0

Answer:

Step-by-step explanation:

Um? I do not thing you showed your answers.

You might be interested in

Show that the points A(-1,2), B (5,2) and C (2,5) are the vertices of an isosceles triangle. Find the area of ∆ABC

EastWind [94]

Answer:

the area of ∆ABC = 9

Step-by-step explanation:

$CA=\sqrt{\left( -1-2\right)^{2} +\left( 2-5\right)^{2} } = \sqrt{18} =3\sqrt{2}$

$CB=\sqrt{\left( 5-2\right)^{2} +\left( 2-5\right)^{2} } = \sqrt{18} =3\sqrt{2}$

<em>Since</em> CA = CB <em>then</em> A(-1,2), B (5,2) and C (2,5) are the vertices of an isosceles triangle.

Area calculation:

Let The point H be the midpoint of side AB

$x_{H}=\frac{-1+5}{2} =2\\y_{H}=\frac{2+2}{2} =2$

Then

H(2 , 2)

therefore,

$CH=\sqrt{\left( 2-2{}\right)^{2} +\left( 2-5\right)^{2} } =3$

Finally,

$\text{the area of triangle ABC} =\frac{\text{CH} \times \text{AB} }{2} =\frac{3\times 6}{2} =9$

5 0

2 years ago

Can you answer number 20

Natasha2012 [34]

The numbers go as followed, from top to bottom: 11,13,15

3 0

3 years ago

Read 2 more answers

Find the volume will give brainlest

harkovskaia [24]

7693/3 is what i got i think it’s right

4 0

3 years ago

Can someone PLZZZZ HELP!!!!

swat32

Answer:

The solution is:

Part A. $\sqrt{5}^{\frac{7k}{3}})$ which is sqrt(5)^7k/3[/tex]

Part B. k = 18/7

Step-by-step explanation:

Part A.

To solve this part, we're going two use THREE important properties of exponents:

1. $(x^{n})^{m} = x^{nm}$

2. $\frac{x^{n}}{x^{m}} = x^{n-m}$

3. $\sqrt[n]{x^{m}} = x^{\frac{m}{n} }$

Let's work the numerator using the properties 1, 2 and 3:

$(\sqrt{5}^{3} )^{\frac{k}{9} } } = (\sqrt{5}^{3\frac{k}{9}}) = (\sqrt{5}^{\frac{k}{3}})$

Let's work the denominator using the properties 1, 2 and 3:

$(\sqrt{5}^{6} )^{-\frac{k}{3} } } = (\sqrt{5}^{6\frac{k}{3}}) = (\sqrt{5}^(2k))$

Now dividing the numerator by the denominator:

$\sqrt{5}^{\frac{k}{3}-(-2k)})=\sqrt{5}^{\frac{7k}{3}})$

Part B

if $5^{\frac{3}{2} } 5^{\frac{3}{2}} = \sqrt{5}^{\frac{7k}{3}})$

Then:

$5^{3} = 5^{\frac{7k}{6}})$

So $\frac{7k}{6}} = 3$

Solving for k, we have:

k = 18/7

7 0

4 years ago

1.) Jeffjust bought a house on a triangular lot. The

zhannawk [14.2K]

Answer:176 feet

Step-by-step explanation:because you multiply all sides of the triangle

3 0

3 years ago