Ask question

Ask question

All categories

2 years ago

14

Find the difference. 8 - 4 = 1

2 answers:

spin [16.1K]2 years ago

5 0

Answer:

8 - 4 =4

Step-by-step explanation:

Anvisha [2.4K]2 years ago

3 0

Eight minus four equals four!

You might be interested in

A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10

Iteru [2.4K]

Answer:

$1,139\ shoppers$

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

a is the initial value or y-intercept

b is the base of the exponential function

r is the rate in decimal form

b=(1+r)

In this problem we have

x ----> the number of days

y ----> the number of shoppers

a=120

r=10%=10/100=0.10

b=1+0.10=1.10

substitute the values

$y=120(1.10)^{x}$

First day

$y=120$

Second day

For x=1 day

substitute the value of x in the equation and solve for y

$y=120(1.10)^{1}=132$

Third day

For x=2 days

$y=120(1.10)^{2}=145$

Fourth day

For x=3 days

$y=120(1.10)^{3}=160$

Fifth day

For x=4 days

$y=120(1.10)^{4}=176$

Sixth day

For x=5 days

$y=120(1.10)^{5}=193$

Seventh day

For x=6 days

$y=120(1.10)^{6}=213$

Adds the numbers

$120+132+145+160+176+193+213=1,139$

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to 4(x-3) ?

Lunna [17]

Answer:

To find the answer you just have to solve 4(x-3)

Step-by-step explanation:

4(x-3)=4x-12

So B or 4x-12 is correct.

5 0

2 years ago

Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph

Dennis_Churaev [7]

ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

$f(x)=x^4-x^3-7x^2+13x-6$

According to rational roots theorem,

$\pm1,\pm2,\pm3,\pm6$ are possible rational zeros of

$f(x)=x^4-x^3-7x^2+13x-6$ .

We find out that,

$f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6$

$f(-3)=81+27-63-39-6$

$f(-3)=6-6$

$f(-3)=0$

Also

$f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6$

$f(2)=16-8-28+26-6$

$f(2)=6-6$

$f(2)=0$

This implies that

$x-2 and x+3$ are factors of

$f(x)=x^4-x^3-7x^2+13x-6$ and hence $(x-2)(x+3)=x^2+x-6$ is also a factor.

We perform the long division as shown in the diagram.

Hence,

$f(x)=(x-2)(x+3)(x-1)^2$ .

ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots

$x=2$ and $x=-3$ have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.

Also the root $x=1$ has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.

Now we determine the position of the graph on the following intervals,

$x\le -3$

$f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6$

$f(-4)=150\:>0$

$-3\le x \le 1$

$f(0)=-6\:$

$1\le x\le 2$

$f(1.5)=-0.56\:$

$x \ge 2$

$f(3)=24\:>0$

We can now use these information to sketch the function as shown in diagram

4 0

3 years ago

Hey answer this <br> y2-x if y=7, x = - 7<br> the 2 is an exponent<br> and show your work

VladimirAG [237]

Plug them in..
1. (7)^2-(-7) = (7)•(7)-(-7)
2. 49-(-7) = 49+7 (if you are subtracting a negative, change the sign to a plus and take out the negative)
3. Add, 56 is your answer

3 0

3 years ago

I need<br> 1<br> 10<br> of fuel in %

m_a_m_a [10]

Answer:

10%

Step-by-step explanation:

7 0

3 years ago