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Kaylis [27]
3 years ago
9

The volume of a cone is 164 cubic feet. Its height is 12 feet. Ashlyn is finding the area of the base of the cone. Her work is

Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Answer:

d

Step-by-step explanation:

just got 100 percent on quiz

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X/2 is greater than or equal to -4
irga5000 [103]
\frac{x}{2}≥-4

Pretend the greater than or equal to sign is an equal sign, we will substitute it back in later.

x/2 = -4
Multiply both sides by 2 to get x alone
x = -8
Substitute the greater than or equal to sign back in and voila!
x≥-8
3 0
3 years ago
A public health official is planning for the supplyof influenza vaccine needed for the upcoming flu season. She wants to estimat
Marizza181 [45]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

Step-by-step explanation:

We know that the sample proportion have the following distribution:

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that a prior estimation for p would be \hat p =0.5 since we don't have any other info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

5 0
3 years ago
Which expeession can be simplified as 1/n¹⁸ ?
Alex777 [14]

Step-by-step explanation:

the last one is the correct answer

5 0
2 years ago
Read 2 more answers
Line segment GH is divided by point J in the ratio of 1:4. Endpoint G is at (7,5) and point J is at (10, 14).
wlad13 [49]

Answer:

(x2 , y2) = (22,50)

Step-by-step explanation:

Given:

m1 : m2 = 1:4

(x1 , y1) = (7 , 5)

(X ,Y) = (10 ,14)

Find:

(x2 , y2)

Computation:

X = (m1x2 + m2x1) / (m1+m2)

10 = [(1)(x2) + (4)(7)]/(1+4)

10 = [x2 + 28]/5

22 = x2

Y = (m1y2 + m2y1) / (m1+m2)

14 = [(1)(y2) + (4)(5)]/(1+4)

14 = [y2 + 20]/5

70 = y2 + 20

50 = y2

(x2 , y2) = (22,50)

7 0
2 years ago
Park rangers tagged fish in a state park to track their population. The function f(x)=200(1.05)x can be used to find the populat
Sedbober [7]

The given exponential function can be used to determine the

population of the fish at different times.

Response:

1. 200

2. 0.05

3. Please find attached the graph of the exponential function and the table

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. Range; [0, ∞)

Domain: [200, ∞)

5. 346 fishes (approximate value)

<h3>How is the population of the fish obtained from the exponential function?</h3>

The given function is f(x) = 200·(1.05)ˣ

1. The initial population is given by the value of the function when x = 0,

which is given as follows;

At x = 0, f(0) = 200·(1.05)⁰ = 200

  • The initial population of the fish is <u>200</u>

2. The rate of growth of the fish from the exponential function is given as follows;

The growth factor = 1.05

  • The growth rate =<u> 0.05</u>

3. Please find attached the graph of the exponential function created

with MS Excel.

The asymptote of the exponential function is the line, <u>y = 0</u>

The table of values is presented as follows;

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. The domain is the possible x-values which is; 0 ≤ x < ∞

The range is the possible y-values which is; 200 ≤ f(x) < ∞

Which gives;

  • Domain; [0, ∞)
  • Range: [200, ∞)

5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹

f(11) = 200 × (1.05)¹¹ ≈ 342

  • The population of the fish after 11 years is <u>346 (fishes)</u>

Learn more about exponential function here:

brainly.com/question/15662160

3 0
2 years ago
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