The answer is macrophages. They either actively invade these leukocytes or are phagocytosed, divide in the cells and cause lysis. The promastigotes that invade these leucocytes are transformed into amastigotes in the macrophages. These amastigotes continue attacking other healthy macrophages while others migrate to the mid gut.
Answer:
True
Explanation:
<em>The life cycles of sexually producing organisms generally involve alternation between the haploid and diploid generations.</em>
<u>Sexual reproduction involves the fusion of gametes - fertilization. The gametes are haploid (n) and are usually formed by the reductional division (meiosis) of diploid (2n) sex cells. </u>
Haploid gametes represent the haploid stage of the life cycles of sexually reproducing organisms. During fertilization, the male and female gametes fuse together to form a diploid zygote. The zygote then continues to divide equationally (mitosis) and differentiates to give rise to a baby and eventually to either male or female adult organism.
Answer:
On the basis of Chargaff's rule, in a double-helical DNA, A = T and G = C (Here A means adenine, T means thymine, G means guanine, and C means cytosine. For X, A is given 32%, therefore, T must be 32%, and the leftover 36% is to be distributed equally between G and C. Thus, G = C = 18% each.
The assumption formed is that the DNA is a double-stranded structure. The species that exhibits higher G + C content in the molecule of a DNA is steadier at higher temperatures as it melts at high temperature. The species Y, which exhibits G + C in total as 66% is the thermophilic bacterium between the two.
A lipid containing a phosphate group in it's molecule.
Hi! The answer to your question would be D, It is a seeded vascular plant. Hope this helps.
