Answer:
146°
Step-by-step explanation:
Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circle. Given m arch AB=64° and ⦣ABC=73°, m ⦣ABC=__ ° and m arch AC=__ °.
Solution:
Given that:
arc AB = 64° and ⦣ABC=73°
The Central Angle Theorem states that the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points. The inscribed angle is any point along the outer arc AB and the two points A and B.
Therefore arc AC is the central angle of ⦣ABC. Using the central angle theorem gives:
arc AC = 2 * ⦣ABC
substituting:
arc AC = 2 * 73
arc AC = 146°
So you foil out the problem and get
If we draw a diagonal which will also be a transversal DB, then we get ∠ADB is congruent to ∠CBD by Alternate interior angles.
It will be the first option.
To complete the square:
we take the coefficient ox "x" (which in this problem is -20)
we divide it by 2
square that number
then add it to both sides of the equation
-20 / 2 = -10
-10^2 = 100
then we add 100 to both sides of the equation:
x^2 -20x
x^2 -20x +100 = 100
******************************************************
To get the roots of the equation, we take the square root of both sides:
(x -10) * (x-10) = 10
(x-10) = square root (10)
x-10 =
<span>
<span>
<span>
3.1622776602
</span>
</span>
</span>
x1 =
<span>
<span>
<span>
13.1622776602
</span>
and don't forget that square root of 10 also equals </span></span><span><span><span> -3.1622776602
</span>
</span>
</span>
x2 = 10
-<span>
<span>
<span>
3.1622776602
x2 = </span></span></span>
<span>
<span>
<span>
6.8377223398
</span>
</span>
</span>
