All categories

3 years ago

Which transformations could be performed to show that ΔABC is similar to ΔA'B'C'? *

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

6 0

Answer:

a reflection over the y-axis, then a dilation by a scale factor of 1.5

Step-by-step explanation:

im smart

You might be interested in

2x + 4 = 4x how. to solve it

ipn [44]

Answer:

x=2

Step-by-step explanation:

2x+4=4x

-2x -2x

4=2x/2x

4/2=x

x=2

8 0

3 years ago

Read 2 more answers

Best Buy purchases a laptop for $244. They then sell the laptop for $927.20. What is the percent increase in the price?

maria [59]

Answer:

sjbs

Step-by-step explanation:

ywyeyeyjejsjeueuheuehe

6 0

3 years ago

You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building

nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

$h=\sqrt{x^2+y^2}$

The rate of change for the distance between you and the elevator is given by:

$\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}$

$-16=\frac{dh}{dy}*\frac{dy}{dt}$

$\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\$

Applying the chain rule:

$u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}$

Therefore, at x=300 and y = 500, dy/dt is:

$-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s$

The elevator is descending at 18.66 ft/s.

7 0

3 years ago

The

algol [13]

Answer:

I'm not really sure what you're asking because there's no image.

Step-by-step explanation:

please try to reword it and maybe show a picture .

5 0

3 years ago

4. Simplify the expression:

Natalija [7]

Answer:

Step-by-step explanation:

$7x^2-6+4x+7-5x^2+x\qquad\text{combine like terms}\\\\=(7x^2-5x^2)+(4x+x)+(-6+7)\\\\=2x^2+5x+1$

3 0

3 years ago