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PtichkaEL [24]
3 years ago
6

I need help with this plleeeaaaseeee

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer: its the 3 one i think  

hope that help :,)

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Sean counts by 2s from 15 to 35. which number does Sean count?<br><br> HELP ME ASAP!!!
Vladimir [108]

The number that Sean counts is 27.

What number does Sean count?

When Sean counts by 2s from 15 to 35, he would be counting odd numbers. An odd number is a number that cannot be perfectly divided by 2. There would always be a remainder.

Here are the options:

13

27

16

22

To learn more about integers, please check: brainly.com/question/21493341

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2 years ago
Determine the EXACT value of : ( 1235 x 0.24 ) - 1.32​
vovikov84 [41]

Answer:

295.08

Step-by-step explanation:

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3 years ago
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Which best describes the slope of the line in the graph A) zero B) positive C) negative D) undefined
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Answer: Don't know bruh.

Step-by-step explanation:

There isn't a picture or a description Dude

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4 years ago
Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]        

Width for n = 64:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision

5 0
3 years ago
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