<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
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Answer:
320
Step-by-step explanation:
Distance covered by falcon in 2 hours=300*2=600 km
Distance covered by goose in 2 hours=140*2=280 km.
Falcon flew 600-280=320 km more than goose
Answer:
10
Step-by-step explanation:
2n-6
n=8
2(8)-6
16-6
10
The answer is b
The perimeter of a rectangle is 2(l + w) so in this case, it is 2(15 + 9) and that is equal to 48. But so at c and d. So u need to multiply the width by 2 (9*2=18) and then you’ll see that 18-3=15. And therefore, the length is -5 and the width is 9
The speed of wind is 656 kmph and speed of plane is 70 kmph.
<u>SOLUTION:
</u>
Given that, an air-plane travels 4688 kilometers against the wind in 8 hours
And 5808 kilometers with the wind in the same amount of time.
We have to find the rate of the plane in still air and the rate of wind
Now, let the speed of wind be a kmph and speed of plane be b kmph.
And we know that, 
Substituting (1) in (2) we get,
On substituting (3) in (1) we get,
Hence, the speed of wind is 656 kmph and speed of plane is 70 kmph.
