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3 years ago

Select the correct expanded form for (Two-thirds) Superscript 4.

Mathematics

2 answers:

svetlana [45]3 years ago

6 0

The answer would be A., (2/3)^4 just means the number in the parentheses is multiplied by the number beside as in the example 4

Nana76 [90]3 years ago

5 0

Answer:

Step-by-step explanation:

The exponent 4 means it is 2/3 multiplied by itself 4 times.

So it would be 2/3*2/3*2/3*2/3

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Solve 4y - 7 =29 Quickly done

Murljashka [212]

Answer:

y=9

Step-by-step explanation:

4y-7=29

(add 7 to both sides)

4y=36

(divide both sides by 4)

y=9

7 0

3 years ago

Can someone please help me with this similar area question? I have the answer but I’m not sure how to get to it. Will make brain

Mumz [18]

Step-by-step explanation:

well there is a very simple point that you have mistaken tho:

484cm², 25cm²

Areas are defined in square cm but the radius is in cm

so:

$\sqrt{ \frac{484 {cm}^{2} }{25 {cm}^{2} } } = \frac{7.92}{r} = = = > 4.4 = \frac{7.92cm}{x} = = > x = \frac{7.92cm}{4.4} = x = 1.8cm$

and there you go

5 0

2 years ago

Cuál es la solución de la ecuación 9 x + 1 = 2x + 15

arsen [322]

Answer:

X=2

Step-by-step explanation:

9x+1=2x+15

1. restar 1 de ambos lados ejemplo: 9x+1-1=2x+15-1

2. simplificar Ejemplo: 9x=2x+14

3. restar 2x de ambos lados ejemplo: 9x-2x=2x-2x+14

4. simplificar ejemplo: 7x=14

5.divide ambos lados entre 7 ejemplo: 7x/7= 14/7

6.Simplificar ejemplo: x=2

3 0

3 years ago

What’s the approximate value of tan 1

goldfiish [28.3K]

Answer: tan 1 radians = 1.557, tan 1 degrees = 0.017

6 0

2 years ago

(04.05 LC)

Komok [63]

correct answer is option d.

Step-by-step explanation:

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

a. x3 + 3x2 − 5x − 15

For $-\sqrt{3}$ , $x^{3} + 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

b. x3 + 2x2 − 3x − 6

For $-\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6$ = 0 .

For $\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6$ = 0.

For 2 , $x^{3} + 2x^{2} -3x -6$ ⇒ $(2) ^{3} + 2(2)^{2} -3(2 ) -6$ $\neq 0$ . So, this isn't the one. We move on further!

c. x3 − 3x2 − 5x + 15

For $-\sqrt{3}$ , $x^{3}- 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3}- 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

d. x3 − 2x2 − 3x + 6

For $-\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(-\sqrt{3}) ^{3} - 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) +6$ = 0 .

For $\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(\sqrt{3}) ^{3} -2(\sqrt{3} )^{2} -3(\sqrt{3} ) +6$ = 0.

For 2 , $x^{3} - 2x^{2} -3x +6$ ⇒ $(2) ^{3} - 2(2)^{2} -3(2 ) +6$ = 0.

Therefore, correct answer is option d.

6 0

3 years ago