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3 years ago

6X8=------ PLEASE HELP

Mathematics

2 answers:

vovangra [49]3 years ago

7 0

Its 48. Random fact : 48 divided by 8 = 6. xD

Anestetic [448]3 years ago

4 0

6 * 8 = 48 is your answer

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What is 12x^3- 9c^3 -4x + 3

Maksim231197 [3]

Answer: -9c^3−4x+1731

Step-by-step explanation:

12^3-9c^3-4x+3

1728-9c^3-4x+3

-9c^3−4x+(1728+3)

-9c^3−4x+1731

3 0

3 years ago

Please answer the question!

galina1969 [7]

Let five moles of oxygen are required to react with 2 moles of acetylene. So, doing a rule of three, we are going to obtain :

5 moles of Oxygen => 2 moles of C2H2

? O2 => 1 mole of C2H2

1.0 mole C2H2×(5 moles O2/2 moles of C2H2) = 2.5 moles of O2

So, the answer is 2.5 moles of oxygen are required to react with 1 mole of acetylene.

3 0

2 years ago

What does 1/63 look like (show picture)

s2008m [1.1K]

Answer:

do u mean a decimal or a graph bar

Step-by-step explanation:

0.01587301587

5 0

3 years ago

The square root of a product of two positive real numbers is the product of their square roots. Write an algebraic expression ba

Sliva [168]

Step-by-step explanation:

The square root of a product of two positive real numbers is the product of their square roots.

Let 4 and 5 be the two positive real number. The square root of a product of 4 and 5 is the product of their square roots.

$\sqrt{4\cdot 5}$

$=\sqrt{20}$

$=\sqrt{2^2\cdot \:5}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

$=\sqrt{5}\sqrt{2^2}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a$

$\sqrt{2^2}=2$

Therefore,

$\sqrt{4\cdot \:5}=2\sqrt{5}$

NOW SOLVING BY APPLYING RADICAL RULE such that

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

$\sqrt{4\cdot 5}=\sqrt{4}\sqrt{5}$

$\sqrt{2^2}=2$

$=2\sqrt{5}$

Hence, The square root of a product of two positive real numbers is the product of their square roots.

5 0

3 years ago

Help me please :))))

AlladinOne [14]

The answer is 3 beautiful lady

3 0

3 years ago