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Serga [27]
3 years ago
12

The square root of a product of two positive real numbers is the product of their square roots. Write an algebraic expression ba

sed on that statement.
Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Step-by-step explanation:

  • The square root of a product of two positive real numbers is the product of their square roots.

Let 4 and 5 be the two positive real number. The square root of a product of 4 and 5 is the product of their square roots.

\sqrt{4\cdot 5}

=\sqrt{20}

=\sqrt{2^2\cdot \:5}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

=\sqrt{5}\sqrt{2^2}

so

=\sqrt{5}\sqrt{2^2}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

\sqrt{2^2}=2

Therefore,

\sqrt{4\cdot \:5}=2\sqrt{5}

NOW SOLVING BY APPLYING RADICAL RULE such that

\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

\sqrt{4\cdot 5}=\sqrt{4}\sqrt{5}

as

\sqrt{2^2}=2

so

     =2\sqrt{5}            

Hence, The square root of a product of two positive real numbers is the product of their square roots.

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A package being delivered in the mail weighs 1056 ounces. How much does that package weigh in pounds?
Vlad1618 [11]

Answer:

66

Step-by-step explanation:

16 oz equal a pound so 1056 divided by 16

5 0
3 years ago
Segment XY bisects angle WXZ and angle mZXY = 37 degrees. Find angle mWXY and angle mZXW
Vadim26 [7]

we know that

The angle bisector, is the line or line segment that divides the angle into two equal parts.

So

in this problem

m∠ZXW=m∠WXY+m∠ZXY

m∠WXY=m∠ZXY

Part a) <u>Find the value of m∠WXY</u>

m∠ZXY=37°-----> given value

so

m∠WXY=m∠ZXY=37°

therefore

<u>the answer part a)</u>

The measure of angle WXY is equal to 37°

Part b) <u>Find the value of m∠ZXW</u>

m∠ZXW=m∠WXY+m∠ZXY

m∠ZXW=37°+37°=74°

therefore

<u>the answer part b) is</u>

the measure of angle ZXW is 74 degrees

8 0
3 years ago
An apartment complex has a floor plan with dimensions shown. To effectively air condition a room, 20 BTU’s are required for ever
kifflom [539]

12,900 BTU's are required to cool the room effectively.

Step-by-step explanation:

Step 1:

We must calculate the area of the entire shape to determine the minimum BTU's required to cool the room effectively.

It is made up of a semi-circle a rectangle, and a trapezoid.

Step 2:

The area of a semi-circle =\frac{ \pi r^{2} }{2} .

Here, the diameter is 20 feet so the radius is 10 feet.

The area of the semi-circle =\frac{ \pi r^{2} }{2} =\frac{ (\pi) (10^{2}) }{2} = 157.079 square feet.

The area of a rectangle = (l)(w).

The length of the rectangle is 22 feet and the width is 20 feet.

The area of a rectangle = (l)(w) =(22)(20) = 440 square feet.

The area of a trapezoid =\frac{a+b}{2} (h).

Here a=12, b= 20, h= 3.

The area of a trapezoid =\frac{12+20}{2} (3) = 48 square feet.

Step 3:

The total area of the floor plan =157.079+440+48 = 645.079 square feet.

If 20 BTU's are required for a single square foot,

The number of BTU's for 645.079 square feet = (645.079)(20)=12,901.58 BTU's.

Rounding this off, we get 12,900 BTU's required  to cool the room effectively.

7 0
3 years ago
Edison is a hard-working college junior. On Saturday, he decides to work nonstop until he has answered 100 practice problems for
kiruha [24]

Answer: at twice the father's rate of speed. At this rate; how many miles would the bicycle rider travel in 9 hours?

Step-by-step explanation:

at twice the father's rate of speed. At this rate; how many miles would the bicycle rider travel in 9 hours?

5 0
3 years ago
Find the slope of the tangent line to the given polar curve at the point specified by the value of θ
MariettaO [177]

The given curve has equation

<em>r(θ)</em> = 9 + 8 cos(<em>θ</em>)

and its derivative is

d<em>r</em>/d<em>θ</em> = -8 sin(<em>θ</em>)

When <em>θ</em> = <em>π</em>/3, we have <em>r</em> (<em>π</em>/3) = 13, and d<em>r</em>/d<em>θ</em> (<em>π</em>/3) = -4√3.

Differentiate these with respect to <em>θ</em> :

d<em>y</em>/d<em>θ</em> = d<em>r</em>/d<em>θ</em> sin(<em>θ</em>) + <em>r(θ)</em> cos(<em>θ</em>)

d<em>x</em>/d<em>θ</em> = d<em>r</em>/d<em>θ</em> cos(<em>θ</em>) - <em>r(θ</em>) sin(<em>θ</em>)

In polar coordinates, we have

<em>y(θ)</em> = <em>r(θ)</em> sin(<em>θ</em>)

<em>x(θ)</em> = <em>r(θ)</em> cos(<em>θ</em>)

and when <em>θ</em> = <em>π</em>/3, we have <em>y</em> (<em>π</em>/3) = 13√3/2 and <em>x</em> (<em>π</em>/3) = 13/2.

The slope of the tangent line to the curve is d<em>y</em>/d<em>x</em>. By the chain rule,

d<em>y</em>/d<em>x</em> = d<em>y</em>/d<em>θ</em> • d<em>θ</em>/d<em>x</em> = (d<em>y</em>/d<em>θ</em>) / (d<em>x</em>/d<em>θ</em>)

d<em>y</em>/d<em>x</em> = (d<em>r</em>/d<em>θ</em> sin(<em>θ</em>) + <em>r(θ)</em> cos(<em>θ</em>)) / (d<em>r</em>/d<em>θ</em> cos(<em>θ</em>) - <em>r(θ</em>) sin(<em>θ</em>))

When <em>θ</em> = <em>π</em>/3, the slope is

d<em>y</em>/d<em>x</em> = (-4√3 sin(<em>π</em>/3) + 13 cos(<em>π</em>/3)) / (-4√3 cos(<em>π</em>/3) - 13 sin(<em>π</em>/3))

d<em>y</em>/d<em>x</em> = (-4√3 (√3/2) + 13 (1/2)) / (-4√3 (1/2) - 13 (√3/2))

d<em>y</em>/d<em>x</em> = - 1/(17√3)

So, the tangent line has slope -1/(17√3) and passes through (13/2, 13√3/2). Using the point-slope formula, its equation is

<em>y</em> - 13√3/2 = -1/(17√3) (<em>x</em> - 13/2)

<em>y</em> = -(<em>x</em> - 338)/(17√3)

4 0
3 years ago
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