Please help with this question
1 answer:
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Answer:
Step-by-step explanation:
Add to both sides:
Subtract 2 from both sides:
Divide both side by 2:
Answer:
(-∞,-3) and (3,∞)
Step-by-step explanation:
f(x) = x³ − 27x + 3
1. Find the critical points
(a) Calculate the first derivative of the function.
f'(x) = 3x² -27
(b) Factor the first derivative
f'(x)= 3(x² - 9) = 3(x + 3) (x - 3)
(c) Find the zeros
3(x + 3) (x - 3) = 0
x + 3 = 0 x - 3 = 0
x = -3 x = 3
The critical points are at <em>x = -3</em> and x = 3.
2. Find the local extrema
(a) x = -3
f(x) = x³ − 27x + 3 = (-3)³ - 27(-3) + 3 = -27 +81 + 3 = 57
(b) x = 3
f(x) = x³ − 27x + 3 = 3³ - 27(3) + 3 = 27 - 81 + 3 = -51
The local extrema are at (-3,57) and (3,-51).
3, Identify the local extrema as maxima or minima
Test the first derivative (the slope) over the intervals (-∞, -3), (-3,3), (3,∞)
f'(-4) = 3x² -27 = 3(4)² - 27 = 21
f'(0) = 3(0)² -27 = -27
f'(4) = 3(4)² - 27 = 51
The function is increasing on the intervals (-∞,-3) and (3,∞).
The graph below shows the critical points of your function.
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Answer:
- positive
- negative
Step-by-step explanation:
The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.
That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.
If k is subtracted, instead of added, then the point will be moved downward.
The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.
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<em>Comment on the question</em>
The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.
If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.
