The Sydney cricket ground can contain a football field of approximately 147m by 136m. What distance would be covered by walking
1 answer:
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The complete question in the attached figure
we know that
in the triangle BDC
cos alfa=3/y----------> equation 1
sin alfa=x/y----------> equation 2
in the triangle ABD
cos alfa=4/5--------> equation 3
sin alfa=3/5---------> equation 4
then
Equal equation 1 and 3
3/y=4/5---------> y/3=5/4----------> y=15/4
Equal equation 2 and 4
x/y=3/5-------> x=3*y/5------------> 3*15/(4*5)-----> x=9/4
the answer is
<span>x=9/4 y=15/4</span>
we know that
in the triangle BDC
cos alfa=3/y----------> equation 1
sin alfa=x/y----------> equation 2
in the triangle ABD
cos alfa=4/5--------> equation 3
sin alfa=3/5---------> equation 4
then
Equal equation 1 and 3
3/y=4/5---------> y/3=5/4----------> y=15/4
Equal equation 2 and 4
x/y=3/5-------> x=3*y/5------------> 3*15/(4*5)-----> x=9/4
the answer is
<span>x=9/4 y=15/4</span>
Answer:
Cost price of each candy = $0.80, Selling price of each candy = $1.40
Step-by-step explanation:
Given:
Ramiro buys 50 packs of candy bars for $40 before a tax of 7.5%.
He sells each candy var for 175% of what he paid before tax.
Question asked:
How much does he buy each candy bar for ?
How much does he sell one for ?
Solution:
<u>By unitary method:</u>
Cost of 50 packs of candy bars = $40
Cost price of 1 pack of candy bars =
Cost price of each candy = $0.80
Thus, he buy each candy bar for $0.80
Now:-
As he sells each candy var for 175% of what he paid before tax:-
Selling price of each candy = 0.80 175%
=
Thus, he sell one candy for $1.40