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Mice21 [21]
3 years ago
11

The Sydney cricket ground can contain a football field of approximately 147m by 136m. What distance would be covered by walking

around the field?
Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0
The answer is 566m because 147 plus 147 and 136 plus 136 equals 566
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Rom4ik [11]

Answer:

C

Step-by-step explanation:

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3 years ago
Read 2 more answers
CAN ANYONE HELP ME WITH QUESTION 6
Kitty [74]
SINCE THATS AN ISOSCELES TRIANGLE:

AB=BC

SO 3x-4=5x-10

But we have to find x

3x-4=5x-10

Minus 3x on both sides

-4=2x-10

Add 10 on both sides

6=2x

Divide 2 on both sides

3=x

So x is 3

Now since we are looking for side AB which is 3x-4

Substitute in 3 as x

3(3)-4

9-4=5

So 5 is the answer.

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2 years ago
1 minus 2 over x minus 3 over x squared divided by 1 minus 9 over x squared
Wittaler [7]
Are you familiar with PEMDAS?

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8 0
3 years ago
Joelle would like to tip her hairdresser 20%. If her haircut costs $38. 00, which expression should she use to find the tip amou
3241004551 [841]

The expression Joelle should use to find the tip amount is 38(0.20).

<h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.  

<h2>Given to us</h2>

Percentage tip of Joelle hairdresser = 20%,

Joelle's haircut costs = $38,

<h3>Percentage Conversion</h3>

As we know that  percentage shows a part of something, therefore,

20\%\ of\ \$38\\= 20\% \times 38\\\\= \dfrac{20}{100}\times 38\\\\= 0.2 \times 38

Hence, the expression Joelle should use to find the tip amount is 38(0.20).

Learn more about expression:

brainly.com/question/13947055

5 0
3 years ago
Paul plays a video game that is scored by round . In about 500 rounds his career average is 20 points per round with a standard
DanielleElmas [232]

Answer:

The mean of the sampling distribution is 20 and the standard deviation is 2.89.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Mean 20, standard deviation of 5.

Sampling distribution:

3 rounds

Mean = 20

s = \frac{5}{\sqrt{3}} = 2.89

The mean of the sampling distribution is 20 and the standard deviation is 2.89.

5 0
3 years ago
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