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Sedbober [7]
3 years ago
13

In a class of 7, there are 3 students who have done their homework.

Mathematics
1 answer:
max2010maxim [7]3 years ago
5 0

Answer:

4/35

Step-by-step explanation:

Probability of 1 student having no hw is 4/7, then 3/6, then 2/5

4/7 x 3/6 x 2/5 reduces to 4/35

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Can someone help me with this two because I am very confused
Tasya [4]

Answer:

Let the height of the larger box = h

and length and width of the larger box = l and w , repectively

Now , Let find the volume of the larger box

Volume = length * width * height

So Volume of the larger box = l*w*h = lwh

Now the question says

the height of the smaller box is 80% of the height of the larger box

It means

Height of the smaller box = 80% of h = 0.80*h = 0.80h

and the other two dimensions are same so it means length and width of the smaller box = l and w

so, Volume of the smaller box = l*w*0.80h = 0.80lwh

So the Difference in the volume of the two boxes = Volume of larger box - Volume of smaller box

therefore , Difference in the Volume of two boxes = lwh - 0.80 lwh = 0.20lwh

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The value of the intercept for the graph of 4x-5y=40 i s<br> A 10<br> B 4/5 <br> C-4/5 <br> D -8
sveta [45]

b option is right

4/5

Mark me as brainlist

5 0
3 years ago
What is the first 6 multiplies of 8
erik [133]

Answer:

8,16,24,32,40, and 48

Step-by-step explanation:

first 6 multiplies of 8 are 8,16,24,32,40, and 48

hope it helps u!

8 0
3 years ago
According to a 2014 Gallup poll, 56% of uninsured Americans who plan to get health insurance say they will do so through a gover
Airida [17]

Answer:

a) 24.27% probability that in a random sample of 10 people exactly 6 plan to get health insurance through a government health insurance exchange

b) 0.1% probability that in a random sample of 1000 people exactly 600 plan to get health insurance through a government health insurance exchange

c) Expected value is 560, variance is 246.4

d) 99.34% probability that less than 600 people plan to get health insurance through a government health insurance exchange

Step-by-step explanation:

To solve this question, we need to understand the binomial probability distribution and the binomial approximation to the normal.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The variance of the binomial distribution is:

V(X) = np(1-p)

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

56% of uninsured Americans who plan to get health insurance say they will do so through a government health insurance exchange.

This means that p = 0.56

a. What is the probability that in a random sample of 10 people exactly 6 plan to get health insurance through a government health insurance exchange?

This is P(X = 6) when n = 10. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.56)^{6}.(0.44)^{4} = 0.2427

24.27% probability that in a random sample of 10 people exactly 6 plan to get health insurance through a government health insurance exchange

b. What is the probability that in a random sample of 1000 people exactly 600 plan to get health insurance through a government health insurance exchange?

This is P(X = 600) when n = 1000. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 600) = C_{1000,600}.(0.56)^{600}.(0.44)^{400} = 0.001

0.1% probability that in a random sample of 1000 people exactly 600 plan to get health insurance through a government health insurance exchange

c. What are the expected value and the variance of X?

E(X) = np = 1000*0.56 = 560

V(X) = np(1-p) = 1000*0.56*0.44 = 246.4

d. What is the probability that less than 600 people plan to get health insurance through a government health insurance exchange?

Using the approximation to the normal

\mu = 560, \sigma = \sqrt{246.4} = 15.70

This is the pvalue of Z when X = 600-1 = 599. Subtract by 1 because it is less, and not less or equal.

Z = \frac{X - \mu}{\sigma}

Z = \frac{599 - 560}{15.70}

Z = 2.48

Z = 2.48 has a pvalue of 0.9934

99.34% probability that less than 600 people plan to get health insurance through a government health insurance exchange

4 0
3 years ago
Can someone explain this for me??<br> 4 (c+2) &lt; 4c + 10
faust18 [17]

Answer:

The inequality would be true

Step-by-step explanation:

4(c+2) < 4c + 10

Distribute the 4 on the left

4c + 8 < 4c + 10

Subtract 4c from both sides

8 < 10

8 < 10 is true

7 0
3 years ago
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