First it is reflected in the x axis (beacuse the x value becomes negative but the y values stays the same)
second its dilated by a factor of a half ( the sides of the figure are reduced by a half)
then its translated 2 units to the left and 2 units upwards
Answer:
1.3
Friend is wrong
Step-by-step explanation:
Given:
friend's claim: height of his building is more than 1.50 times the height of yours
line of sight to the top edge of the other building makes an angle of 21° above the horizontal
line of sight to the base of the other building makes an angle of 52° below the horizontal
Solution:
Let A be the height of your building is A
Let B+A his building is B higher than yours.
Let the distance between the buildings is x.
then
tan 52 = A/x
tan 21 = B/x
A/B = tan 52 / tan 21
= 1.27994 / 0.38386
A/B = 3.33
(A + B) / A = 1.5
0
A/A + B/A = 1.50
1 + B/A = 1.50
B/A is basically (B/x) / (A/x)
So
1+ 3.33 / 3.33
= 4.33/3.33
= 1.3
Since 1.3 is not equal to 1.5
Hence the friend's claim is wrong.
Answer:
2 : 14
Step-by-step explanation:
<h2>
Answer with explanation:</h2>
Let 
be the average starting salary ( in dollars).
As per given , we have
Since 
is left-tailed , so our test is a left-tailed test.
WE assume that the starting salary follows normal distribution .
Since population standard deviation is unknown and sample size is small so we use t-test.
Test statistic : 
, where n= sample size , 
= sample mean , s = sample standard deviation.
Here , n= 15 , 
, s= 225
Then, 
Degree of freedom = n-1=14
The critical t-value for significance level α = 0.01 and degree of freedom 14 is 2.62.
Decision : Since the absolute calculated t-value (2.07) is less than the critical t-value., so we cannot reject the null hypothesis.
Conclusion : We do not have sufficient evidence at 1 % level of significance to support the claim that the average starting salary of the graduates is significantly less that $42,000.
