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skelet666 [1.2K]
3 years ago
13

What is the distance across the patch of swamp water

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

about 45 feet please believe me i'm making an educated guess

You might be interested in
English
larisa86 [58]

Answer:

6 square feet

Step-by-step explanation:

Carpet has w= 8 ft and l = 12 ft

Reduced carpet has w' = 2 ft

<u>Reduction factor is </u>

  • 8/2 = 4

<u>Then </u>

  • l' = l/4 = 12/4 = 3 ft

<u>Area of small carpet</u>

  • S = 2*3 = 6 ft²
6 0
3 years ago
I need help with this plz
Morgarella [4.7K]

Answer:

i would go with B

Step-by-step explanation:

I'm not too sure I'm so sorry but thats my closest guess

8 0
2 years ago
1. Try It #1
padilas [110]

Answer:

The slope of the line representing the linear function f(x) is determined as $-\frac{1}{2}$. The function f(x) is decreasing because the slope is less than zero, i.e., m<0.

Step-by-step explanation:

A linear function f(x) is given with two points, (2,3) and (0,4) lying on the line representing f(x).

It is asked to determine the slope of the line and state if the function is increasing or decreasing. of the value of the slope obtained.

Step 1 of 1

Determine the slope of the line.

The points as given in the question are (2,3) and (0,4). Now, the formula for the slope is given as

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

So, substitute $4 \& 3$ for $y_{2}$ and $y_{1}$ respectively, and $0 \& 2$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,$m=\frac{4-3}{0-2}$\\ $m=\frac{1}{-2}$\\ $m=-\frac{1}{2}$

The slope of the line is obtained as $-\frac{1}{2}$. Now, as $-\frac{1}{2} < 0$, so the function f(x) is decreasing.

7 0
1 year ago
For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
Question 20: Please help what are sin x and cos x?
sweet [91]

Answer:

A is the correct answer.

Step-by-step explanation:

\tan x =   \frac{6}{8}  =  \frac{opposite \: side \: to \:  \angle \: x}{adjacent \: side \: to \:  \angle \: x}  \\  \\ hypotenuse  \\ =  \sqrt{ {(opp. \: side)}^{2} +  {(adj. \: side)}^{2}  }  \\  =  \sqrt{ {6}^{2} +  {8}^{2}  }  \\  =  \sqrt{36 + 64}  \\  =  \sqrt{100}  \\  = 10 \\  \\ \because  \sin (x) =  \frac{opposite \: side \: to \:  \angle \: x}{hypotenuse}  \\  \\   \huge{ \red{ \boxed{\therefore \: \sin (x) =  \frac{6}{10}}}}  \\  \\ \cos (x) =  \frac{adjacent \: side \: to \:  \angle \: x}{hypotenuse}  \\  \\  \huge{ \purple{ \boxed{\therefore \: \cos (x) =  \frac{8}{10} }}} \\

Thus, option A is the correct answer.

8 0
3 years ago
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