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OverLord2011 [107]
3 years ago
12

Please help me no one would help me I really need help due today

Mathematics
2 answers:
hram777 [196]3 years ago
3 0

Answer:

(1). V=\pi  r^2l+\frac{1}{3}\pi r^2  h

(2).a. 25\pi square feet

  b. 158.33\pi cubic feet

Step-by-step explanation:

(1).

The rocket is made up of a cylinder and a cone, this means its total volume V is

V =V_{cylinder}+V_{cone}

Now

V_{cylinder} = \pi r^2l

V_{cone} = \frac{1}{3}\pi  r^2h

Thus

\boxed{V=\pi  r^2l+\frac{1}{3}\pi r^2  h}

(2).

a. The floor is a disk with diameter 10/2 = 5 feet; therefore, its area A is  

A=\pi r^2=\pi (5ft)^2

\boxed{A=25\pi }

b.

The volume of the space inside the observatory V_{obs} is equal to the volume of the cylinder and the hemisphere:

V_{obs} =V_{hemisphere}+V_{cylinder}

V_{hemisphere}=\frac{1}{2}* \frac{4}{3}\pi  r^3=83.33\pi ft^3

V_{cylinder}=\pi (5)^2(3)=75\pi

Thus

V_{obs}=83.33\pi ft^3+75\pi ft^3=\boxed{158.33ft^3}

taurus [48]3 years ago
3 0

Answer:

Step-by-step explanation:

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