Question

Please help me no one would help me I really need help due today

Answer 1

Answer:

(1). $V=\pi r^2l+\frac{1}{3}\pi r^2 h$

(2).a. $25\pi$ square feet

  b. $158.33\pi$ cubic feet

Step-by-step explanation:

(1).

The rocket is made up of a cylinder and a cone, this means its total volume $V$ is

$V =V_{cylinder}+V_{cone}$

Now

$V_{cylinder} = \pi r^2l$

$V_{cone} = \frac{1}{3}\pi r^2h$

Thus

$\boxed{V=\pi r^2l+\frac{1}{3}\pi r^2 h}$

(2).

a. The floor is a disk with diameter 10/2 = 5 feet; therefore, its area $A$ is  

$A=\pi r^2=\pi (5ft)^2$

$\boxed{A=25\pi }$

b.

The volume of the space inside the observatory $V_{obs}$ is equal to the volume of the cylinder and the hemisphere:

$V_{obs} =V_{hemisphere}+V_{cylinder}$

$V_{hemisphere}=\frac{1}{2}* \frac{4}{3}\pi r^3=83.33\pi ft^3$

$V_{cylinder}=\pi (5)^2(3)=75\pi$

Thus

$V_{obs}=83.33\pi ft^3+75\pi ft^3=\boxed{158.33ft^3}$

Answer 2

Answer:

Step-by-step explanation: