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Eva8 [605]
3 years ago
11

Ayudenmee plis

Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

El intervalo, con un nivel de confianza de 99%, para estimar el sueldo medio poblacional de los trabajadores es de ($1807, $2193).

Step-by-step explanation:

El primero paso es el encuentro de lo \alpha, que es la subtracion de 1 por lo nivel de confianza e divididos por 2. Entonces:

\alpha = \frac{1 - 0.99}{2} = 0.005

Ahora, buscamos a z en la tabela Z de manera que z tienga uno p-value de 1 - \alpha.

Entonces, z con uno p-value de 1 - 0.005 = 0.995, o sea, z = 2.575.

La margen de error es:

M = z\frac{\sigma}{\sqrt{n}}

En que \sigma es la desviación estándar y n es el tamaño de la muestra.

σ=$600. Si se tomó una muestra de 64 trabajadores

Entonces \sigma = 600, n = 64

Margen de error:

M = z\frac{\sigma}{\sqrt{n}}

M = 2.575\frac{600}{\sqrt{64}}

M = 193

El limite inferior es la subtración de la media de la muestra por la margen de error. Entonces 2000 - 193 = $1807.

El limite inferior es la suma de la media de la muestra con la margen de error. Entonces 2000 + 193 = $2193.

El intervalo, con un nivel de confianza de 99%, para estimar el sueldo medio poblacional de los trabajadores es de ($1807, $2193).

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the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0. What is the value of q?the equation -2x^2+3=-9x is rewritte
Novosadov [1.4K]

Value of q is \frac{105}{8} .

<u>Step-by-step explanation:</u>

We have , the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0 . We need to find What is the value of q . Let's find out:

Let's simplify equation -2x^2+3=-9x into -2(x-p)^2 +q=0 :

⇒ -2x^2+3=-9x

⇒ -2x^2+9x+3=0

⇒ 2x^2-9x=3

⇒ 2(x^2-\frac{9}{2}x)=3

⇒ (x^2-\frac{9}{2}x)=\frac{3}{2}

⇒ (x^2-2(1)\frac{9}{4}x)=\frac{3}{2}

⇒ (x^2-2(1)\frac{9}{4}x) + (\frac{9}{4})^2=\frac{3}{2} + (\frac{9}{4})^2

⇒ (x-\frac{9}{4})^2=\frac{3}{2} + (\frac{81}{16})

⇒ (x-\frac{9}{4})^2=\frac{24}{16} + (\frac{81}{16})

⇒ (x-\frac{9}{4})^2=\frac{105}{16}

⇒ -2(x-\frac{9}{4})^2=-2(\frac{105}{16})

⇒ -2(x-\frac{9}{4})^2=-\frac{105}{8}

⇒ -2(x-\frac{9}{4})^2+\frac{105}{8} = 0

Comparing this equation to -2(x-p)^2 +q=0 , q =\frac{105}{8} .

Therefore ,Value of q is \frac{105}{8} .

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