I hope this helps you
10 1/2 + 10 + 7 + 6 + 3 1/2 +4
10+1/2+27+3+1/2
40+1/2+1/2
40+2/2
40+1
41
Answer:
25 and 30
Step-by-step explanation:
Let the smaller consecutive multiples of 5 be x. Therefore, other consecutive multiples will be x + 5.
Now as per statement the sum of two consecutive multiples of 5 is 55. To find the multiples. Thus
x + x + 5 = 55
2x + 5 = 55
2x = 55 - 5
2x = 50
x = 50/2
x = 25
This the smaller consecutive multiples of 5 is 25, the other consecutuve multiple is x+ 5, 25 + 5 = 30.
The consecutive multiple numbers of 5 are 25 and 30
Answer the two consecutive multiples of 5 are 25 and 30
Answer:
y = -2x -2
x + 2y = 2
2x + y = -2 } x1
x + 2y = 2 } x2
2x + y = -2 } we eliminate 2x
2x + 4y = 4 } same signs subtract and different add respectively
-3y = -6
-3 -3
y = 2 (x , 2) we reserve
2x + (2) = -2 we take on the first equation and replace 2 on a coordinate for y
2x = -2 - 2
2x = -4
2 2
x = -2 (-2,2)
x y
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + ( x + 2) = 267...combine like terms
3x + 3 = 267...subtract 3 from both sides
3x = 267 - 3
3x = 264
x = 264/3
x = 88
x + 1 = 88 + 1 = 89
x + 2 = 88 + 2 = 90
the largest will be 90
