I need some help with thsi

Mathematics

1 answer:

Norma-Jean [14]3 years ago

4 0

Answer:

$slope \ of \ y = 2x + 5 , m_{1} = 2\\\\Let \ the \ slope \ of \ the \ new \ line \ be \ m_{2} \\Since \ the \ lines \ are \ parallel \ m_{1} \cdot m_{2} = 1\\$

$That \ is \ 2 \cdot m_{2} = 1 => m_{2} = \frac{1}{2}$

Equation of line passing through (2, -4)

$y-(-4)= \frac{1}{2} (x - 2)\\\\$

$y+4 = \frac{1}{2} ( x - 2)\\\\2y + 8 = x - 2\\\\2y = x -10\\y = \frac{1}{2} x -5$

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Convert the rate of 10 yards per 5 minutes to feet per hour

jenyasd209 [6]

10 yards per 5min is

10yrd/5min

first convert it into yards per minute

10yrds/5min = 2yrds/1min

let's first so the yards to feet part first

1 yrd = 3 feet

2yrds/min * 3ft/1yrd

so now we have

6yrds/min

now convert minute to hour

1 hour = 60 mins

6yrds/min * 60min/1hr

=360/1hr

remember so that units cancel

5 0

4 years ago

Read 2 more answers

Use the Factor Theorem and synthetic division to show x + 5 is a factor of f(x) = 2x3 + 7x2 − 14x + 5

olga2289 [7]

Answer:

Factor theorem: $f(-5) = 0$ .

Synthetic division: $f(x) = (x + 5)\, (2\, x^2 -3\, x + 1)$ .

Step-by-step explanation:

<h3>Factor Theorem</h3>

By the factor theorem, a monomial of the form $(x - a)$ (where $a$ is a constant) is a factor of polynomial $f(x)$ if and only if $f(a) = 0$ .

In this question, the monomial is $(x + 5)$ , which is equivalently $(x - (-5))$ . $a = -5$ .

$\begin{aligned}& f(-5) \\ &= 2 \times (-5)^{3} + 7 \times (-5)^{2}- 14\times (-5) + 5\\ &= -250 + 175 + 70 + 5 \\ &= 0\end{aligned}$ .

Hence, by the factor theorem, $(x + 5)$ , which is equivalent to $(x - (-5))$ , is a factor of $f(x)$ .

<h3>Synthetic Division</h3>

$\begin{aligned}& f(x) \\ &= 2\, x^{3} + 7\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} - 3\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} + \underbrace{(x + 5)\, (-3\, x)}_{-3\, x^{2} - 15\, x} + (x + 5) \\ &= (x + 5)\, (2\, x^{2} - 3\, x + 1)\end{aligned}$ .