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natima [27]
2 years ago
5

Please help I’m stuck on this one!

Mathematics
1 answer:
4vir4ik [10]2 years ago
3 0

Answer: The length of JK is 10.5 m

Step-by-step explanation:

Find the circumference C= dπ

C = 12π

C= 37.7

There are 360 degrees in a circle's circumference, so you can find the length of the arc by using the ratio of the arc to the whole circumference.

Multiply the Circumference by 100/360  (or 5/18 × 37.7)

The arc is 10.5 m

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Step-by-step explanation:

To find slope, use two points.

Point A (x_{1},y_{1}) and Point B (x_{2}, y_{2}).

Slope (m) = \frac{y_{2}-y_{1} }{x_{2}-x_{1}}.

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2 years ago
BESTIES HELP ME PLEASE ANSWER THIS CORRECLTY, PLEASE TELL ME WHICH ONE OF THESE IS A LINEAR EQUATION, AND WHICH ONE IS NOT. YOU'
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Step-by-step explanation:

Which of what? There is no ss.

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3 years ago
Anastasia gets overtime (time and a half) for every hour she works over 40 hours. If her hourly pay is $28.50, how much would sh
tamaranim1 [39]

Answer:

142.50

Step-by-step explanation:

28.50=1 hour so you would do 28.50 times the amount of hours she works. She worked 51 hours so you would do 28.50x50. You answer is 142.50

7 0
3 years ago
Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
Please help ASAP please
mihalych1998 [28]

do you some help ?, I can try my best to help

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2 years ago
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