ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:

Step-by-step explanation:
From the question we are told that:
Sample size 
Amount used 
Generally the equation for sugar lift
is given as is mathematically given by



Exponential Function.
Plotting the graph using this table gives the first figure. An exponential function has this kind of graph.
Answer:
Step-by-step explanation:
i dont know the answrrrr
If I’m correct then it is 0.25