Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where 
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:
Substitute the respective values in the above formula.
Hence, the required probability is 0.55404.
Okay well the mode is the number that appears most pften for ex 112351 the mode is 1 because it is the number that is there more than the others
Answer: g(h(x))=6x +1 and h(g(x)) = 6x+7
Step-by-step explanation: Basically , this is a substitution exercise.
g(h(x)) = g(2x-1) . Now substitute x = 2x-1 in for x in g(x)
hence g(2x-1) = 3(2x-1)+4 = 6x - 3 + 4 = 6x + 1
Similarly : h(g(x)) = h(3x+4) substitute x = 3x+4 in h(x)
hence h(3x+4) = 2(3x + 4 ) - 1 = 6x + 8 - 1 = 6x + 7
We have been given that a right circular cone has a height of 12.2 cm and a base with a circumference of 18.5 cm. We are asked to find the volume of the cone to nearest tenth.
We know that circumference of circle is equal to 
.
Now we will use volume of the cone formula to solve our given problem.
Upon rounding to nearest tenth, we will get:
Therefore, the volume of the given cube would be approximately 110.8 cubic centimeter.
Answer:
620 minutes
Step-by-step explanation
In one day,Mata exercise 20minutes more than Greg
31 days so we have 20 *31=620
