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3 years ago

Please help I found this one a bit confusing

Mathematics

1 answer:

Brums [2.3K]3 years ago

4 0

Answer:

7.2

Step-by-step explanation:

To reach point D from point C, you need to add 4 to the x-value of point C and take away 6 from the y-value. These numbers are the sides of the hypothetical triangle.

The Pythagorean Theorem states that $a^2+b^2=c^2$ . If we plug the side lengths in for a and b, we get $4^2 + 6^2 = c^2$ . This can be simplified to $16+36=c^2$ , or $52 = c^2$ . If we root both sides, we find that c is equal to $\sqrt{52}$ , which is slightly more than 7, at around 7.2.

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Find LCM of: x2 - 9, 3x3 + 81

VikaD [51]

Answer:

$\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}$

Step-by-step explanation:

Given two expressions ,

$\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81$

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :- 

$= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]$

Factorising 3x³ + 81 

$= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }$

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

8 0

3 years ago

PLEASE HELP Indicate the method you would use to prove the two 's . If no method applies, enter "none".

irakobra [83]

Yes that's AAS because the two triangles have two angles in common and a side opposite to 30 degrees angle.

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3 years ago

Read 2 more answers

Lena is going to cover her entire garden with topsoil. The garden is 36 feet long by 22 feet wide. A bag of topsoil costs $3 and

OLEGan [10]

$9.00 because, 36*22=792 Feet.
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4 years ago

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Where is the question at

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3 years ago

4.01 Homework please

natka813 [3]

Answer:

hope this helps :)

Step-by-step explanation:

a) yes, this is a polygon (shape with 4 sides)

b) the polygon is a concave

c) equilateral

d) this type of polygon is called 'arrowhead'

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3 years ago

Please help I found this one a bit confusing ​

Please help I found this one a bit confusing