Write a cubic function whose graph passes through the points (-4,0)(4,0)(0,6) and (2,0)

Mathematics

1 answer:

gulaghasi [49]3 years ago

3 0

Answer: 3/16(x+4)(x-4)(x-2)

Step-by-step explanation:

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What is %*+-fgfghfhfjgjhj

lions [1.4K]

Answer:

Easy

Step-by-step explanation:

Easy to use and easy to use and easy to use onenote

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3 years ago

Can anyone help me with this. It asks to solve and check your answer.

Katarina [22]

4m -21 = 3(5m - 1)
4m - 21 = 15m - 3
15m - 4m = -21 + 3
11m = -18
m = -18/11

To check:
LHS → 4 (-18/11) -21 = - 303/11
RHS → 3( 5(-18/11) - 1) = -303/11
LHS = RHS (The answer is right)

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3 years ago

Can u guys PLEASE answer question 26 and 27. THIS IS URGENT

Nadya [2.5K]

Step-by-step explanation:

$(26) \\ \frac{m}{3} - 4 \geqslant \frac{m - 2}{4} \\ \\ \therefore \: \frac{m - 12}{3} \geqslant \frac{m - 2}{4} \\ \\ \therefore \:\frac{4(m - 12)}{12} \geqslant \frac{3(m - 2)}{12} \\ \\ \therefore \:4m - 48 \geqslant 3m - 6 \\ \\ \therefore \:4m - 3m \geqslant 48 - 6 \\ \\ \huge \red{ \boxed{\therefore \:m \geqslant 42}} \\ \\ (27) \\ \frac{a}{2} - \frac{a - 3}{3} < 5 - \frac{a}{6} \\ \\ \therefore \: \frac{3a - 2a + 6}{6} < \frac{30 - a}{6} \\ \\ \therefore \: \frac{a + 6}{6} < \frac{30 - a}{6} \\ \\ \therefore \: a + 6 < 30 - a \\ \\ \therefore \: a + a < 30 - 6 \\ \\ \therefore \: 2 a < 24 \\ \\ \therefore \: a < \frac{24}{2} \\ \\ \huge \orange{ \boxed{\therefore \: a < 12}}$

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3 years ago

How do i solve things that dont make sense to me even though i do know but dont know

kirill [66]

Answer:

Just try to make it make sense to you.

Step-by-step explanation:

For instance, a + 1 = 5

a = 4

We know that we should switch the terms as when it comes to normal numbers ,10 + 1 = 11 , 10 = 11-1. Therefore, the only trick is not to memorise, but try to understand the logic behind it. Hope this helps in some way???

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2 years ago

Please help as soon as possible.

nalin [4]

Answer:

Step-by-step explanation:

this is a continuous function

it passes the vertical line test and have 2 zeros: -1 and 2;

the domain is from negative infinity to infinity

the range is $[-3, \infty]$

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3 years ago