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3 years ago

How do u write an equation in slope intercept form to describe a graph

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

Answer:

y= mx+b BRAINLIEST PLEASE

Step-by-step explanation:

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The equivalent expression for (x-6)(4)

hoa [83]

Answer:

(x-6)(4) = 4x-24 (Answer is 4x-24)

Step-by-step explanation:

<h2><u>(x-6)(4) so you do this read it </u></h2><h2><u>so the steps are =(x+−6)(4)</u></h2><h2><u>=(x)(4)+(−6)(4) so then you will get 4x-24</u></h2><h2><u></u></h2>

6 0

3 years ago

You do not need to flip the inequality sign when solving the inequality -3t + 7 ≥ 9. True False

nordsb [41]

Hello!

It is False because t is multiplied by a negative number, so to solve for it you will need to divide both sides by -3 which mean you have to flip the sign.

Hope this helps!

7 0

3 years ago

For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?

STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

$z=\frac{x-\mu}{\sigma}$

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of $-0.25$ .

Upon substituting our given values in z-score formula, we will get:

$-0.25=\frac{x-500}{100}$

$-0.25*100=\frac{x-500}{100}*100$

$-25=x-500$

$-25+500=x-500+500$

$x=475$

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0

3 years ago

Blank plus 1/2 equals 8/10

Eduardwww [97]

Answer:

8/5

Step-by-step explanation:

Hope This Helps;)

8 0

3 years ago

2v^2-12 =-12v <br> Would really appreciate it loves❤️

Black_prince [1.1K]

For this case we have the following equation:

$2v ^ 2-12 = -12v$

Rewriting we have:

$2v ^ 2 + 12v-12 = 0$

Dividing by 2 to both sides of the equation:

$v ^ 2 + 6v-6 = 0$

We apply the quadratic formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have to:

$a = 1\\b = 6\\c = -6$

Substituting:

$x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}$

Thus, we have two roots:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

ANswer:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

7 0

3 years ago

How do u write an equation in slope intercept form to describe a graph​

How do u write an equation in slope intercept form to describe a graph