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lisabon 2012 [21]
3 years ago
10

Given the two triangles shown, find the value of x

Mathematics
1 answer:
Volgvan3 years ago
5 0

Answer: x = 150/6 = 25

Step-by-step explanation:

Here is the information shown in the diagram: in triangle ABC, Angle A = 68, Angle C = 38, AB = 6, and BC = 10. In triangle DEF, Angle D = 38, Angle E = 74, EF = 15, and DE = x.)

The value of x is (Choose...4, 11, 12, 19, 20, 25).

To solve this, we notice that the sum of the angle measures mentioned is 68 + 38 + 74 = 180. Thus Triangles ABC and FED are similar by AA Similarity. It remains only to set up the proportion:

DE/CB = EF/BA

x/10 = 15/6

x = 150/6 = 25

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When factoring an expression, we need to identify the Greatest Common Factor of the expression (GCF). By definition, GCF is the product of prime factors involved with its Lowest Exponent.

We need to divide each term by the GCF to get the expression inside the parenthesis.

30a^6-24a^2\\ GCF\; is \; 6a^2\\ \\ 30a^6-24a^2=6a^2(\frac{3a^6}{6a^2} -\frac{24a^2}{6a^2} )=6a^2(5a^4-4)\\ ---------------------\\ \\ 16a^5-20a^3\\ GCF \; is \; 4a^3\\ \\ 16a^5-20a^3=4a^3(\frac{16a^5}{4a^3} -\frac{20a^3}{4a^3})=4a^3(4a^2-5) \\ ---------------------\\ \\ 12a^3+8a\\ GCF \; is \; 4a\\ \\ 12a^3+8a=4a(\frac{12a^3}{4a}+\frac{8a}{4a})=4a(3a^2+2)\\   ---------------------\\ 24a^4+18\\GCF \; is \; 6\\\\24a^4+18=6(\frac{24a^4}{6} +\frac{18}{6})=6(4a^4+3) \\    ---------------------

Conclusion:

From above we can conclude that the below expressions are factored completely

16a^5-20a^3=4a^3(4a^2-5)\\ \\ 24a^4+18=6(4a^4+3)

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