The correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.
<h3>What is interval notation?</h3>
It is defined as the representation of a set of values that satisfy a relation or a function. It can be represented as open brackets and close bracket the close the brackets means the value is at the close bracket also included, and open bracket means the value at the open bracket does not include.
We have:
Continuous set of all numbers between 5 and 6, including 5, but not including 6.
From the above statement we can represent the number in the interval notation:
The numbers are between 5 and 6.
(5, 6)
As it is mentioned that 5 is included and 6 is not included, then:
[5, 6)
Thus, the correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.
Learn more about the interval notation here:
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Answer:
54%
Step-by-step explanation:
Answer:
C & D
Step-by-step explanation:
x² + 3x - 3 = 0
a = co efficient of x² = 1
b= co efficient of x = 3
c = constant = -3
roots = (-b ± )/2a
= (-3± )/2*1
= (-3±)/2
= (-3±√21)/2
Answer:
So it would takes approximately 6.9 hours to reach 32 F.
Step-by-step explanation:
For this case we have the following differential equationÑ
We can reorder the expression like this:
We can use the substitution and so then we have:
IF we integrate both sides we got:
If we apply exponential in both sides we got:
And if we replace w = u-T we got:
We can also express the solution in the following terms:
For this case we know that since w ehave a cooloing, , we have this model:
And if we want that the temperature would be 32F we can solve for t like this:
If we apply natural logs on both sides we got:
So it would takes approximately 6.9 hours to reach 32 F.
Y=-3x-2
subsitute -3x-2 for y
-7x+3(-3x-2)=10
distribute
a(b+c)=ab+ac
3(-3x-2)=-9x-6
-7x-9x-6=10
add like terms
-16x-6=10
add 6
-16x=16
multiply -1
16x=-16
divide 16
x=-1
subsitute
y=-3x-2
y=-3(-1)-2
y=3-2
y=1
x=-1
y=1
(x,y)
(-1,1)