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Slav-nsk [51]
3 years ago
15

Which inequality best represents the situation? A bamboo stalk grows at a rate of 3 centimeters per day. Lisa plants a 9-centime

ter bamboo stalk in her yard. How many days will it take for the stalk to be at least 300 cm tall?
Mathematics
1 answer:
pav-90 [236]3 years ago
8 0
Let x represent the days it will take for the stalk to be at least 300 cm tall

3x+9≥300
3x≥291
x≥97
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3 years ago
E the problem
Lera25 [3.4K]

Answer:

D) (0.59, 3.35)​

Step-by-step explanation:

The inequality for the thickness of the metal bars is:

|x-1.971| \leq1.38

In order for this inequality to be true, the following conditions must be met:

x-1.971 \leq1.38\\x-1.971 \geq -1.38

The range of thickness "x" that fits the inequality is:

x -1.971 \leq1.38\\x\leq 3.351\\x-1.971 \geq -1.38\\x\geq 0.591\\0.59\leq x\leq 3.35

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7 0
3 years ago
$53,000 is placed in an investment account that grows at a fixed rate of 2% (compound growth) per year. how much is in the accou
ella [17]

Answer:

$57,369

Step-by-step explanation:

We have been given that an amount of $53,000 is placed in an investment account that grows at a fixed rate of 2% (compound growth) per year. We are asked to find the amount in the account after 4 years.

To solve our given problem we will use compound interest formula.\

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

Let us convert our given rate in decimal form.

2\%=\frac{2}{100}=0.02

Upon substituting our given values in compound interest formula we will get,

A=\$53,000(1+\frac{0.02}{1})^{1*4}

A=\$53,000(1+0.02)^{4}

A=\$53,000(1.02)^{4}

A=\$53,000*1.08243216

A=\$57368.90448\approx \$57,369

Therefore, an amount of $57,369 will be in the account after 4 years.

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3 years ago
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3 years ago
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astra-53 [7]

Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:

x = x₀ + vt

Velocity can be calculated as:

v=\frac{x-x_{0}}{t}

v=\frac{70-40}{10}

v = 3 m/s

The beginning of the data collect, object is 40m away, then x₀ = 40.

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