Evaluate 2(s+t)^3-6when s = 3 and t = 2
1 answer:
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The value of k is -6
Step-by-step explanation:
The general form of the quadratic equation is y = ax² + bx + c
- The roots of the equation is the values of x when y = 0
- ax² + bx + c = 0, is used to find the roots
∵ 2x² + 11x = -k
- Add k to both sides
∴ 2x² + 11x + k = 0
∵ The roots of the quadratic equations is the values of x when y = 0
∵ is a root of the equation
- Substitute x by in the equation above to find k
∵ 2( )² + 11(
) + k = 0
∴ 2( ) +
+ k = 0
∴ +
+ k = 0
- Add the like terms
∵ +
=
= 6
∴ 6 + k = 0
- Subtract 6 from both sides
∴ k = -6
The value of k is -6
Learn more:
You can learn more about the quadratic equations in brainly.com/question/8196933
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