Evaluate 2(s+t)^3-6when s = 3 and t = 2
1 answer:
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Answer:
No graph so we'll use the quadratic formula
x^2+x-4=0
a = 1
b = 1
c = -4
x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2
x = (-1 +- sqr root (1 +16) ) / 2
x1 = (-1 + sqr root (17)) / 2
x2 = (-1 - sqr root (17)) / 2
Step-by-step explanation:
