Answer:
x=2 and y= -3
Step-by-step explanation:
This is a simultaneous equation. To solve this type of equation, there are three methods; substitution, Elimination and Graphical.
But here, we would be using the substitution method.
3x-y=9 Equation 1
2x-y=7. Equation 2
Getting y from equation 2, we have
-y= 7-2x
Multiply both sides by -
y= 2x-7 Equation 3
Substituting y for 2x-7 in equation 1, we have
3x- (2x-7)=9
3x-2x+7=9
x+7=9
x=9-7
x=2
Substituting x as 2 in equation 3
y=2x-7
y= 2(2)-7
y= 4-7
y= -3
Answer:
Well... "Alphabets" in math, are defined as variables...
And we use variables to show the things that we are multiplying, dividing, subtracting, or adding. Like: Beach balls=B "Tommy has to blow up 20 beach balls before he can go to the beach, his mom offers to help him. How many beach balls do each of them have to blow up?" One equation we could use is "B/2 or B divided by 2" :)
Step-by-step explanation:
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero
x+6=0
x=-6
x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6
use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1
the numbers are -4,-5,-6
Answer:
Distributive property
Step-by-step explanation:
The 2 is distributed over the parentheses (x + y) the the z is also.
