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Fynjy0 [20]
3 years ago
13

Bob has a dog who weighs 12 pounds. His cat weighs 2/3 as much as the dog. How many pounds does his cat weigh?

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0
The dog weighs 12 lbs.
The cat weighs 2/3 as much as the dog


- Divide 12 by 3
= 4

- Then multiply by 2
= 8

His cat weighs 8 pounds.
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In △ABC , m∠A=53°,m∠B=17°, and a=27. Find the perimeter of the triangle.
sdas [7]
Using the Law of Sines  (sinA/a=sinB/b=sinC/c) and the fact that all triangles have a sum of 180° for their angles.

The third angle is C is 180-53-17=110°

27/sin53=b/sin17=c/sin110

b=27sin17/sin53, c=27sin110/sin53

And the perimeter is a+b+c so

p=27+27sin17/sin53+27sin110/sin53 units

p≈68.65 units  (to nearest hundredth of a unit)
6 0
2 years ago
2/8 = ?/32 Find the missing numbers that make the fractions equivalent
horrorfan [7]
The answer is 8/32 because 8 x 4 = 32
3 0
3 years ago
Read 2 more answers
Thank you for your help.
Nonamiya [84]

Answer:

q = -15

Step-by-step explanation:

5q = -75

Divide both sides by 5 : q = -15

8 0
1 year ago
T÷5/12= -3/10<br> Thank you if you help :)
skelet666 [1.2K]

Answer:

t = -1/8.

Step-by-step explanation:

t / 5/12 = -3/10          Invert the 5/12 and multiply:

12t / 5 = -3/10

Cross multiply:

12t * 10 = 5 * -3

120t = -15

t = -15/120 = -1/8.

7 0
2 years ago
Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9
AnnZ [28]

Answer:

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

Step-by-step explanation:

We have been given that

f(x)=x^3-27,g(x)=3x-9

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes -  a^3-b^3=(a-b)(a^2+ab+b^2)

f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)

And g(x) can be written as

g(x)=3x-9\\=3(x-3)

Thus, we have

(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}

On cancelling the common factors, we get

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

5 0
2 years ago
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