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AleksAgata [21]
3 years ago
11

Which of the following comparisons is true? 24,762 = 24,662 335,989 > 335,998 454,909 887,012

Mathematics
1 answer:
ratelena [41]3 years ago
8 0
454,909 < 887,012 <===
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Deshaun made 143 for 11 hours of work. At the same rate, how much would he make for 9 hours of work?
Ivanshal [37]

Answer:

117

Step-by-step explanation: 143\11=13

then multiply 13 by 9 and that equals 117

7 0
3 years ago
Read 2 more answers
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Which term best describes he statement given below? If x =&gt; y and y=&gt; z, then x=&gt; z
Ierofanga [76]

Answer:d


Step-by-step explanation:


7 0
3 years ago
A 11 and 1/4
solong [7]

Answer:

Step-by-step explanation:

i dont know the answrrrr

3 0
3 years ago
It takes 24 megabytes to store 144 songs on a music player. What is the greatest number of songs that 60 megabytes could store?
givi [52]

Option B

We can store a total of 360 songs in 60 megabytes of space.

<u>Solution:</u>

It is given to us that It takes 24 megabytes to store 144 songs on a music player. We have been asked to find out what is the greatest number of songs that 60 megabytes could store.

To solve this question we can use the unitary method.  

We will first find out how many songs can be stored in 1 megabyte. This can be done as follows:

=\frac{144}{24}=6

Therefore, we can store 6 songs in 1 megabyte.

So, in 60 megabyte we can store the following number of songs:

=60 \times 6=360

So, we can store a total of 360 songs in 60 megabytes.

8 0
4 years ago
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